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Applications of Ampere’s Circuital Law > Magnetic Field of a Long Straight Thin Wire

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Estimated time: 5 minutes
CISCE: Class 12

Introduction

Every current-carrying conductor generates a magnetic field around it. Just as ripples spread in concentric circles when a stone is dropped in water, magnetic field lines form concentric circles around a straight current-carrying wire — this section derives the exact strength of that field using Ampere's Circuital Law.

CISCE: Class 12

Derivation

Step 1 - Setup: Consider a long straight wire carrying current I. Choose a circular Amperian loop of radius r, centred on the wire, lying in a plane perpendicular to it.

Step 2 - Symmetry: By symmetry, \[\vec{B}\] has the same magnitude at every point on the loop and is directed tangentially (along the circle).

Step 3 - Apply the Law: \[\oint\vec{B}\cdot d\vec{l}=B(2\pi r)\]

Step 4 - Equate to enclosed current: B(2πr) = μ0I

Step 5 - Result: B = \[\frac {μ_0I}{2πr}\]

CISCE: Class 12

Example

Given: A long straight wire carries 10 A current flowing from east to west.

Point Distance & Position Formula Used Calculated Field Direction
A 10 cm north B = μ0I/2πr 2 × 10−5 T Vertically downward
B 20 cm south B = μ0I/2πr 1 × 10−5 T Vertically upward
C 40 cm below wire B = μ0I/2πr 5 × 10−6 T Horizontally south
D 50 cm above wire B = μ0I/2πr 4 × 10−6 T Horizontally north

Method: Substitute I = 10A and the given r into B = μ0I/(2πr); apply the right-hand palm rule to fix direction.

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