Statement
When unpolarised light is incident on the surface of a transparent medium at a particular angle, the reflected light becomes completely plane-polarised.
This angle of incidence is called the polarising angle or Brewster’s angle (ip).
According to Brewster’s Law, the refractive index n of the medium is related to the polarising angle by:
n = tan ip
Explanation / Proof
Consider unpolarised light incident on the surface of a transparent medium (e.g., air–glass interface) at the polarising angle ip.
Let:
- ip = angle of incidence (polarising angle)
- r = angle of refraction
- n = refractive index of the second medium w.r.t. the first
From Snell’s law:
n = \[\frac {sin i_p}{sin r}\]
From Brewster’s law:
n = tan ip = \[\frac {sin i_p}{cos i_p}\]
Equating the two expressions for n:
\[\frac{\sin i_p}{\sin r}=\frac{\sin i_p}{\cos i_p}\]
⇒ sin r = cos ip
⇒ sin r = sin(90∘ − ip)
⇒ r = 90∘ − ip
Hence,
ip + r = 90∘
Therefore, the reflected ray and refracted ray are mutually perpendicular.
Conclusion
- Brewster’s law establishes a direct relation between refractive index and polarising angle:
n = tan ip
- At the polarising angle:
Reflected light is completely plane-polarised
Reflected and refracted rays are perpendicular to each other
- This law explains the polarisation of light by reflection and is a strong confirmation of the transverse nature of light waves