Shaalaa.com | K.E. and P.E. in S.H.M
Obtan an expression for potential energy of a particle performing S.H.M. What is the value of potential energy at (i) Mean position, and (ii) Extreme position
The kinetic energy of nitrogen per unit mass at 300 K is 2.5 × 106 J/kg. Find the kinetic energy of 4 kg oxygen at 600 K. (Molecular weight of nitrogen = 28, Molecular weight of oxygen = 32)
If the frequency of incident light falling on a photosensitive material is doubled, then the kinetic energy of the emitted photoelectron will‘be........................................
Calculate the average molecular kinetic energy :
(a) per kilomole, (b) per kilogram, of oxygen at 27°C.
(R = 8320 J/k mole K, Avogadro's number = 6*03 x 1026 molecules/K mole)
Obtain an expression for potential energy of a particle performing simple harmonic motion. Hence evaluate the potential energy
- at mean position and
- at extreme position.
Prove the law of conservation of energy for a particle performing simple harmonic motion.Hence graphically show the variation of kinetic energy and potential energy w. r. t. instantaneous displacement.