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Overview: Magnetic Fields Due to Electric Current

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Estimated time: 33 minutes
Maharashtra State Board: Class 12

Formula: Magnetic Force on a Moving Charge

Fm= q(v × B)

Maharashtra State Board: Class 12

Definition: Cyclotron Motion

When a charged particle moves perpendicular to a uniform magnetic field, it undergoes uniform circular motion.

Maharashtra State Board: Class 12

Formula: Cyclotron Formula

p = qBR

Maharashtra State Board: Class 12

Formula: Cyclotron Frequency

\[f_c=\frac{1}{T}=\frac{qB}{2\pi m}\]

Maharashtra State Board: Class 12

Formula: Maximum Kinetic Energy of a Particle in a Cyclotron

K.E. = \[\frac{1}{2}\mathrm{mv}^{2}=\frac{q^{2}B^{2}R_{exit}^{2}}{2m}\]

Maharashtra State Board: Class 12

Definition: Helical Motion

When a charged particle enters a uniform magnetic field with velocity having both perpendicular and parallel components to the field, it moves in a helical path.

Maharashtra State Board: Class 12

Formula: Magnetic Force on a Current-Carrying Conductor

F = IL × B

Maharashtra State Board: Class 12

Formula: Force on Arbitrarily Shaped Wire

F = I dl × B

Maharashtra State Board: Class 12

Formula: Force on a Closed Current Loop

F = I dl × B

Maharashtra State Board: Class 12

Formula: Torque on a Current Loop

τ = NIAB sin θ

Where:

  • N = number of turns
  • I = current
  • A = area of the loop
  • B = magnetic field
  • θ = angle between the magnetic field and normal to loop
Maharashtra State Board: Class 12

Formula: Torque on a Magnetic Dipole

τ = μB sin θ

Maharashtra State Board: Class 12

Definition: Moving Coil Galvanometer

A moving coil galvanometer is an instrument used to detect and measure small electric currents based on the torque acting on a current-carrying coil placed in a magnetic field.

Maharashtra State Board: Class 12

Formula: Moving Coil Galvanometer

τ = NIAB

Deflection Relation:

\[\phi=\frac{NAB}{K}I\]

Maharashtra State Board: Class 12

Definition: Magnetic Dipole Moment

The magnetic dipole moment of a current-carrying coil is defined as the product of the number of turns, the current, and the area of the coil.

μ = N I A

Maharashtra State Board: Class 12

Formula: Torque on Magnetic Dipole

τ = μB sin θ

or in vector form,

τ = μ × B

Maharashtra State Board: Class 12

Formula: Magnetic Potential Energy of a Dipole

U = μB

Scalar Form: U = μB cos θ

Umin = μB

Umax= +μB

Maharashtra State Board: Class 12

Law: Biot–Savart Law

Statement

The magnetic field at a point due to a small current element is directly proportional to the current, the length of the element, and the sine of the angle between the current element and the line joining the element to the point, and inversely proportional to the square of the distance between them.

Mathematical Form

Scalar form:

dB = \[\frac{\mu_0}{4\pi}\frac{Idl\sin\theta}{r^2}\]

Vector form:

dB = \[\frac{\mu_{0}}{4\pi}\frac{Id\mathbf{l}\times\mathbf{r}}{r^{3}}\]

where

  • μ0 = permeability of free space
  • I = current
  • dl = current element
  • r = distance from element to point
  • θ = angle between dl and r

Explanation

The total magnetic field at a point due to a current-carrying conductor is obtained by integrating (summing) the contributions of all small current elements along the conductor:

B = ∫ dB

Conclusion

Thus, the Biot–Savart Law gives the magnitude and direction of the magnetic field produced by a current-carrying conductor and follows an inverse square law dependence on distance.

Maharashtra State Board: Class 12

Formula: Magnetic Field due to Long Straight Wire

B = \[\frac{\mu_0I}{2\pi d}\]

Maharashtra State Board: Class 12

Formula: Force Between Two Long Parallel Current-Carrying Wires

\[\frac{F}{L}=\frac{\mu_0I_1I_2}{2\pi d}\]

Maharashtra State Board: Class 12

Formula: Magnetic Field at the Centre of a Full Circular Loop

B = \[\frac{\mu_0I\theta}{4\pi r}\]

For θ = 2π,

B = \[\frac{\mu_0I}{2r}\]

Maharashtra State Board: Class 12

Formula: Axial Magnetic Field of a Circular Current Loop

\[B_z=\frac{\mu_0IR^2}{2(R^2+z^2)^{3/2}}\]

Where:

  • I = current
  • R = radius of loop
  • z = distance of the point from centre along axis
  • μ0 = permeability of free space
Maharashtra State Board: Class 12

Formula: Magnetic Field at the Centre of a Circular Loop

B = \[\frac{\mu_0I}{2R}\]

Magnetic Field at Centre of a Coil (N turns):

B = \[\frac{\mu_0NI}{2R}\]

Maharashtra State Board: Class 12

Law: Ampere’s Circuital Law

Statement

The line integral of the magnetic field around any closed loop is equal to μ₀ times the net current enclosed by the loop.

∮ B ⋅ dl = μ0Ienc

where

  • B = magnetic field
  • dl = small element of the closed loop
  • Ienc = net current enclosed
  • μ0 = permeability of free space

Explanation / Proof 

Consider a long straight wire carrying current I.

Due to cylindrical symmetry:

  • Magnetic field B is tangential to a circular path around the wire.
  • Magnitude of B is the same at all points on a circle of radius r.

Choose a circular Amperian loop of radius r.

Since B and dl are parallel:

∮ B ⋅ dl = ∮ B dl

=B∮dl

=B(2πr)

By Ampere’s Law:

B(2πr) = μ0I

This matches the magnetic field obtained earlier.

Conclusion

Hence,

∮ B ⋅ dl = μ0Ienc

is verified and is known as Ampere’s Circuital Law, a fundamental law of magnetostatics.

Maharashtra State Board: Class 12

Definition: Solenoid

A solenoid is a long, closely wound helical coil of wire that produces a nearly uniform magnetic field inside it when current flows through it.

Maharashtra State Board: Class 12

Formula: Magnetic Field of a Long Solenoid

Magnetic Field Inside a Long Solenoid:

B = μ0ni

Magnetic Field Outside an Ideal Solenoid:

B = 0

Maharashtra State Board: Class 12

Definition: Toroid

A toroid is a solenoid bent into a closed circular (ring-shaped) form.

Maharashtra State Board: Class 12

Formula: Magnetic Field Inside a Toroid

B = \[\frac{\mu_0Ni}{2\pi R}\]

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