Shaalaa.com | Differential equation of linear S.H.M.
A particle performing linear S.H.M. has a period of 6.28 seconds and a pathlength of 20 cm. What is the velocity when its displacement is 6 cm from mean position?
Two particles perform linear simple. harmonic motion along the same path of length 2A and period T as shown in the graph below. The phase difference between them is..............
(a) `zero" "rad`
(b) `pi/4 rad`
(d) `(3pi)/4 rad`
The maximum velocity of a particle performing linear S.H.M. is 0.16 m/s. If its maximum acceleration is 0.64 m/s2, calculate its period.
From differential equation of linear S.H.M., obtain an expression for acceleration, velocity and displacement of a particle performing S.H.M.
A particle executing linear S.H.M. has velocities v1 and v2 at distances x1 and x2 respectively from the mean position. The angular velocity of the particle is _______
A) `sqrt((x_1^2 - x_2^2)/(v_2^2 - v_1^2))`
B) `sqrt((v_2^2 - v_1^2)/(x_1^2 - x_2^2))`
C) `sqrt((x_1^2 + x_2^2)/(v_2^2 + v_1^2))`
D) `sqrt((v_2^2 + v_1^2)/(x_2^2 + x_1^2))`