हिंदी
Maharashtra State BoardSSC (English Medium) 7th Standard

BODMAS Rule

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Topics

  • Introduction
  • Order of Operations
  • Example 1
  • Example 2
  • Real-Life Application
  • Key Points Summary
CISCE: Class 22

Introduction

When solving a math expression with many operations, you must follow one fixed order so that everyone gets the same answer. This order is known as the BODMAS Rule, and it is applied in all mathematics, from simple school problems to advanced calculations.

CISCE: Class 6

Order of Operations

  1. Brackets – Solve inside brackets first.

  2. Of – Find ‘of’ values (fraction of, powers).

  3. Division – From left to right.

  4. Multiplication – From left to right.

  5. Addition – From left to right.

  6. Subtraction – From left to right.

CISCE: Class 6

Example 1

`1/3` +`7/9`  ÷ ( `7/10` × 1 `1/4`)

= `1/3` + `7/9`  ÷ (`7/10` × `5/4`)

=  [`7/10` × `5/4` = `7×5/10×4` = `7/8`]

= `1/3` + `7/9`  ÷ `7/8`

= `1/3` + `7/9`  × `8/7`

= `1/3` + `8/9`

= `3 + 8/9`

= `11/9`

= 1`2/9` 

CISCE: Class 6

Example 2

Simplify: ( `2/3` + `5/9`) of  `9/22` ÷ `2/3` × `4/5` - `1/5`

Solution :
= `11/9` of  `9/22` ÷ `2/3` × `4/5` - `1/5`
[Removing 'bracket', we get:  ( `2/3` + `5/9` = `6 +5 /9` = `11/9` )

=  `1/2` ÷ `2/3` × `4/5` - `1/5`

[ On operating 'of', we get: `11/9` of  `9/22` = `11/9` × `9/22` =  `1/2`]

= `1/2` × `3/2` × `4/5` − `1/5`

= `"1 × 3 × 4" /"2 × 2 × 5"` − `1/5`

= `3/5` − `1/5`

= `2/5`

CISCE: Class 6

Real-Life Application

Imagine sharing chocolates:

  1. First, decide the groups (brackets).

  2. Give half to each (of).

  3. Share equally (division).

  4. Hand out several at once (multiplication).

  5. Count the total given (addition).

  6. Deduct eaten ones (subtraction).

CISCE: Class 6

Key Points Summary

  • Follow BODMAS to solve multi-operation problems correctly.

  • Always start with brackets.

  • Do division/multiplication before addition/subtraction.

  • “Of” means multiplication.

Example Question 1

Solve: 2 × {25 × [(113 - 9) + (4 ÷ 2 × 13)]}

2 × {25 × [(113 - 9) + (4 ÷ 2 × 13)]}
= 2 × {25 × [104 + (4 ÷ 2 × 13)]}
= 2 × {25 × [104 + (2 × 13)]}
= 2 × {25 × [104 + 26]}
= 2 × {25 × 130}
= 2 × 3250
= 6500.

Test Yourself

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