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Area of Triangle using Determinant

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Estimated time: 8 minutes
CBSE: Class 12

Introduction

  • In coordinate geometry, the area of a triangle can be calculated if the coordinates of its vertices are known.

  • Determinants provide a compact and systematic method to calculate this area using a 3 × 3 matrix formed from the coordinates of the vertices.

CBSE: Class 12

Determinant Form of Area

The same area can be expressed in determinant form using a 3 × 3 determinant:

Area of △ABC = \[ \frac{1}{2} \begin{vmatrix} x_1 & y_1 & 1 \\ x_2 & y_2 & 1 \\ x_3 & y_3 & 1 \end{vmatrix}\]

CBSE: Class 12

Properties

  • Area is always non-negative:

    The value of the determinant may be positive or negative, but the area is taken as its absolute value.

  • Sign and $\pm$ in exam problems:

    When the area is given (for example, Area = 12 sq. units), the determinant value can be +24 or -24 because the formula uses \[\frac{1}{2}|\det|\].

  • Condition for collinearity:

    If three points are collinear, the area of the triangle formed by them is zero, so

\[\begin{vmatrix} x_1 & y_1 & 1 \\ x_2 & y_2 & 1 \\ x_3 & y_3 & 1 \end{vmatrix} = 0\]

This is frequently used to check whether three given points lie on the same straight line.

CBSE: Class 12

Key Points: Area of Triangle using Determinant

  • Area of triangle using determinant:

\[ \frac{1}{2} \begin{vmatrix} x_1 & y_1 & 1 \\ x_2 & y_2 & 1 \\ x_3 & y_3 & 1 \end{vmatrix}\]
  • Expanded coordinate form:

    \[\text{Area} = \frac{1}{2}|x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|\].

  • Area is always taken as positive; use absolute value.

  • For collinear points, determinant = 0, so area = 0.

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