मराठी

Refraction of Light Through a Prism

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Estimated time: 6 minutes
CBSE: Class 12

Refraction through a prism

  • At the first face AB, the angle of incidence is i, and the angle of refraction is r1.
  • At the second face AC, the angle of incidence inside the prism is r2 and the angle of emergence is e.
  • The angle between the emergent ray and the direction of the incident ray is called the angle of deviation, δ.
CBSE: Class 12

Relation inside the prism

In the quadrilateral AQNR, two angles are right angles, so the sum of the other two angles is 180 degrees.


From triangle QNR,

  • r1 + r2 + ∠QNR = 180

Comparing the geometric relations, we get:

  • r1 + r2 = A

This is the basic relation inside the prism

CBSE: Class 12

Angle of deviation

The total deviation is the sum of deviations at the two faces.

  • δ = (i − r1) + (e − r2)

Therefore,

  • δ = i + e − A

Thus, the angle of deviation depends on the angle of incidence.

CBSE: Class 12

Derivation

At the minimum deviation Dm​, the refracted ray inside the prism becomes parallel to its base.
At this condition,

  • δ = Dm, i = e

which implies

  • r1 = r2

Using r1 + r2 = A,

  • 2r = A
  • or r = \[\frac {A}{2}\]

Also, from the deviation relation,

  • Dm = 2i − A
  • or i = \[\frac {A+Dm}{2}\]

These are the standard relations for minimum deviation.

Refractive index of the prism

The refractive index of the prism is given by:

  • \[n_{21}=\frac{n_2}{n_1}=\frac{\sin\left(\frac{A+D_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}\]

The angles A and Dm​ can be measured experimentally.
Therefore, this relation provides a method of determining the refractive index of the material of the prism.

Thin prism

For a small-angle prism, that is, a thin prism, DmD_mDm​ is also very small.
Then,

  • \[n_{21}=\frac{\sin\left(\frac{A+D_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}=\frac{\left(\frac{A+D_m}{2}\right)}{\left(\frac{A}{2}\right)}\]

Hence,

  • Dm = (n21 − 1)A

This implies that thin prisms do not deviate light much.

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