Linear equations in two variables
- Linear Equation in Two Variables
- Simultaneous Linear Equations
- Elimination Method
- Substitution Method
- Cross - Multiplication Method
- Graphical Method of Solution of a Pair of Linear Equations
- Determinant of Order Two
- Cramer’s Rule
- Equations Reducible to a Pair of Linear Equations in Two Variables
- Simple Situational Problems
- Pair of Linear Equations in Two Variables
- Quadratic Equations
- Roots of a Quadratic Equation
- Solutions of Quadratic Equations by Factorization
- Solutions of Quadratic Equations by Completing the Square
- Formula for Solving a Quadratic Equation
- Nature of Roots of a Quadratic Equation
- The Relation Between Roots of the Quadratic Equation and Coefficients
- To Obtain a Quadratic Equation Having Given Roots
- Application of Quadratic Equation
- Introduction to Sequence
- Terms in a sequence
- Arithmetic Progression
- General Term of an Arithmetic Progression
- Sum of First n Terms of an A.P.
- Arithmetic Progressions Examples and Solutions
- Geometric Progression
- General Term of an Geomatric Progression
- Sum of the First 'N' Terms of an Geometric Progression
- Geometric Mean
- Arithmetic Mean - Raw Data
- Concept of Ratio
- Probability - A Theoretical Approach
- Basic Ideas of Probability
- Random Experiments
- Equally Likely Outcomes
- Sample Space
- Event and Its Types
- Probability of an Event
- Type of Event - Elementry
- Type of Event - Complementry
- Type of Event - Exclusive
- Type of Event - Exhaustive
- Concept Or Properties of Probability
- Addition Theorem
- Tabulation of Data
- Inclusive and Exclusive Type of Tables
- Ogives (Cumulative Frequency Graphs)
- Applications of Ogives in Determination of Median
- Relation Between Measures of Central Tendency
- Introduction to Normal Distribution
- Properties of Normal Distribution
- Concepts of Statistics
- Mean of Grouped Data
- Method of Finding Mean for Grouped Data: Direct Method
- Method of Finding Mean for Grouped Data: Deviation Or Assumed Mean Method
- Method of Finding Mean for Grouped Data: the Step Deviation Method
- Median of Grouped Data
- Mode of Grouped Data
- Concept of Pictograph
- Presentation of Data
- Graphical Representation of Data as Histograms
- Frequency Polygon
- Concept of Pie Graph (Or a Circle-graph)
- Interpretation of Pie Diagram
- Drawing a Pie Graph
(1) If MV > FV then the share is at premium.
(2) If MV = FV then the share is at par.
(3) If MV < FV then the share is at discount.
For example : (1) suppose FV = Rs. 10, MV = Rs. 15 and 15 - 10 =Rs. 5
∴ The share is at premium of Rs. 5, as MV > FV
(2) suppose FV = Rs. 10, MV = Rs.10 and 10 - 10 = 0
∴The share is at par. As MV = FV
(3) suppose FV = Rs. 10, MV = Rs. 7 and 10 - 7 = 3
∴The share is at discount. As MV < FV.
Sum Invested : Total amount required to purchase the shares is sum invested.
Sum invested = Number of shares × MV
Ex. (1) If 50 shares of FV Rs. 100 each are purchased for MVRs. 120. Find the sum
Solution : Sum invested = number of shares× MV
= 50 × 120 = Rs. 6000
Ex. (2) If you want to purchase 50 shares of MV Rs. 50 each. What is the total
amount to be paid ?
Solution : Sum invested = Number of shares × MV = 50 × 50 =Rs. 2500
Related QuestionsVIEW ALL 
Sangeeta’s monthly income is Rs. 25,000. She spent 90% of her income and donated 3% for socially useful causes. How much money did she save ?
Complete the following table by writting suitable numbers and words.
|Sr.No||FV||Share is at||MV|
|(2)||...||premium Rs 500||Rs 575|
|(3)||Rs 10||...||Rs 5|
Shri Shantilal has purchased 150 shares of FV Rs 100, for MV of Rs 120. Company has paid dividend at 7%. Find the rate of return on his investment.
Market value of a share is Rs 200. If the brokerage rate is 0.3% then find the purchase value of the share.
Prashant bought 50 shares of FV Rs 100, having MV Rs 180. Company gave 40% dividend on the shares. Find the rate of return on investment.
Find the number of shares received when Rs 60,000 was invested in the shares of FV Rs 100 and MV Rs 120.