#### theorem

Suppose f and g be two real functions continuous at a real number c. Then

(1) f + g is continuous at x = c.

(2) f – g is continuous at x = c.

(3) f . g is continuous at x = c.

(4) `(f/g)` is continuous at x = c ,

(provided g(c) ≠ 0).

**Proof:** We are investigating continuity of (f + g) at x = c.

Clearly it is defined at x = c. We have

`lim_(x->c)`(f + g)(x) = `lim_(x->c)`[f(x) + g(x)]

(by defination of f + g)

`lim_(x->c)`f(x) + `lim_(x->c)`g(x)

(by the theorem on limits)

= f(c) + g(c) (as f and g are continuous)

=(f+g)(c) (by defination of f + g)

Hence, f + g is continuous at x = c. Proofs for the remaining parts are similar and left as an exercise to the reader.

**Remarks:**

(i) As a special case of (3) above, if f is a constant function, i.e., f(x) = λ for some real number λ, then the function (λ . g) defined by (λ . g) (x) = λ . g(x) is also continuous. In particular if λ = – 1, the continuity of f implies continuity of – f.

(ii) As a special case of (4) above, if f is the constant function f(x) = λ, then the function `lambda/g` defined by `lambda/g(x)` = `lambda/g(x)` is also continuous wherever g(x) ≠ 0.

In particular, the continuity of g implies continuity of `1/g`

The above theorem can be exploited to generate many continuous functions. They also aid in deciding if certain functions are continuous or not.