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Two masses 8 kg and 12 kg are connected at the two ends of a light, inextensible string that goes over a frictionless pulley. Find the acceleration of the masses,

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प्रश्न

Two masses 8 kg and 12 kg are connected at the two ends of a light, inextensible string that goes over a frictionless pulley. Find the acceleration of the masses, and the tension in the string when the masses are released.

संख्यात्मक
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उत्तर

The given system of two masses and a pulley can be represented as shown in the following figure:

Smaller mass, m1 = 8 kg

Larger mass, m2 = 12 kg

Tension in the string = T

Mass m2, owing to its weight, moves downward with acceleration a,and mass m1moves upward.

Applying Newton’s second law of motion to the system of each mass:

For mass m1:

The equation of motion can be written as:

T – m1g = ma … (i)

For mass m2:

The equation of motion can be written as:

m2g – T = m2a … (ii)

Adding equations (i) and (ii), we get:

(m_2-m_1)g = (m_1+ m_2)a

`:.a = ((m_2-m_1)/(m_1+m_2))g ...(iii)`

`=((12-8)/(12+8)) xx 10= 4/20 xx 10 = 2 "m/s"^2`

Therefore, the acceleration of the masses is 2 m/s2.

Substituting the value of a in equation (ii), we get:

`m_2g - T = m_2 ( (m_2-m_1)/(m_1+m_2))g`

`=((2m_1m_2)/(m_1+m_2))g`

`=(2xx12xx8)/(12+8)xx10`

`=(2xx12xx8)/20 xx 10  = 96 N`

Therefore, the tension in the string is 96 N.

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अध्याय 4: Laws of Motion - EXERCISES [पृष्ठ ७०]

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एनसीईआरटी Physics Part 1 and 2 [English] Class 11
अध्याय 4 Laws of Motion
EXERCISES | Q 4.16 | पृष्ठ ७०

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