हिंदी

A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate: The velocity acquired by the body - Physics

Advertisements
Advertisements

प्रश्न

A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate: The velocity acquired by the body.

संख्यात्मक
Advertisements

उत्तर

Mass, m = 100 kg

Distance moved, s = 100 m

Initial velocity, u = 0

Because the body moves through a distance of 100 m in 5 s,

Velocity of the body = `"Distance moved"/"time taken"`

Velocity = `100/5`

= 20 m/s

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Laws of Motion - Exercise 3 (C) [पृष्ठ ७०]

APPEARS IN

सेलिना Concise Physics [English] Class 9 ICSE
अध्याय 3 Laws of Motion
Exercise 3 (C) | Q 7.1 | पृष्ठ ७०

संबंधित प्रश्न

Explain why a cricketer moves his hands backwards while holding a catch.


A monkey of mass 40 kg climbs on a rope in given Figure which can stand a maximum tension of 600 N. In which of the following cases will the rope break: the monkey

(a) climbs up with an acceleration of 6 m s–2

(b) climbs down with an acceleration of 4 m s–2

(c) climbs up with a uniform speed of 5 m s–1

(d) falls down the rope nearly freely under gravity?

(Ignore the mass of the rope).


You are travelling in a car. The driver suddenly applies the brakes and you are pushed forward. Why does this happen?


Show that the rate of change of momentum = mass × acceleration. Under what condition does this relation hold?


Use Newton's second law of motion to explain the following instance : 

A cricketer pulls his hands back while catching a fast moving cricket ball .


Name the physical entity used for quantifying the motion of a body.


Which of the following has the largest inertia?


Use Newton's second law to explain the following:
While catching a fast moving ball, we always pull our hands backwards.


A stone is dropped from a tower 98 m high. With what speed should a second stone be thrown 1 s later so that both hit the ground at the same time?


The motion of a particle of mass m is given by x = 0 for t < 0 s, x(t) = A sin 4 pt for 0 < t < (1/4) s (A > o), and x = 0 for t > (1/4) s. Which of the following statements is true?

  1. The force at t = (1/8) s on the particle is – 16π2 Am.
  2. The particle is acted upon by on impulse of magnitude 4π2 A m at t = 0 s and t = (1/4) s.
  3. The particle is not acted upon by any force.
  4. The particle is not acted upon by a constant force.
  5. There is no impulse acting on the particle.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×