English

A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate: The velocity acquired by the body

Advertisements
Advertisements

Question

A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate: The velocity acquired by the body.

Numerical
Advertisements

Solution

Mass, m = 100 kg

Distance moved, s = 100 m

Initial velocity, u = 0

Because the body moves through a distance of 100 m in 5 s,

Velocity of the body = `"Distance moved"/"time taken"`

Velocity = `100/5`

= 20 m/s

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Laws of Motion - Exercise 3 (C) [Page 70]

APPEARS IN

Selina Concise Physics [English] Class 9 ICSE
Chapter 3 Laws of Motion
Exercise 3 (C) | Q 7.1 | Page 70

RELATED QUESTIONS

Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. A horizontal force F = 600 N is applied to

  1. A,
  2. B along the direction of string. What is the tension in the string in each case?

A batsman deflects a ball by an angle of 45° without changing its initial speed which is equal to 54 km/h. What is the impulse imparted to the ball? (Mass of the ball is 0.15 kg.)


The force of buoyancy exerted by the atmosphere on a balloon is B in the upward direction and remains constant. The force of air resistance on the balloon acts opposite the direction of velocity and is proportional to it. The balloon carries a mass M and is found to fall to the earth's surface with a constant velocity v. How much mass should be removed from the balloon so that it may rise with a constant velocity v?


Consider the situation shown in the following figure  All the surfaces are frictionless and the string and the pulley are light. Find the magnitude of acceleration of the two blocks.


Let m1 = 1 kg, m2 = 2 kg and m3 = 3 kg in the following figure. Find the accelerations of m1, m2 and m3. The string from the upper pulley to m1 is 20 cm when the system is released from rest. How long will it take before m1 strikes the pulley?


Calculate the tension in the string shown in the following figure. The pulley and the string are light and all the surfaces are frictionless. Take g = 10 m/s2.


A body of mass 5 kg is moving with velocity 2 m s-1. Calculate its linear momentum.


Multiple Choice Question. Select the correct option.

The impulse of a body is equal to:


The position time graph of a body of mass 2 kg is as given in figure. What is the impulse on the body at t = 0 s and t = 4 s.


Why is catching a slow-moving ball easier than catching a fast-moving ball?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×