English

A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate: The velocity acquired by the body

Advertisements
Advertisements

Question

A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate: The velocity acquired by the body.

Numerical
Advertisements

Solution

Mass, m = 100 kg

Distance moved, s = 100 m

Initial velocity, u = 0

Because the body moves through a distance of 100 m in 5 s,

Velocity of the body = `"Distance moved"/"time taken"`

Velocity = `100/5`

= 20 m/s

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Laws of Motion - Exercise 3 (C) [Page 70]

APPEARS IN

Selina Concise Physics [English] Class 9 ICSE
Chapter 3 Laws of Motion
Exercise 3 (C) | Q 7.1 | Page 70

RELATED QUESTIONS

A smooth wedge A is fitted in a chamber hanging from a fixed ceiling near the earth's surface. A block B placed at the top of the wedge takes time T to slide down the length of the wedge. If the block is placed at the top of the wedge and the cable supporting the chamber is broken at the same instant, the block will.


A man has fallen into a ditch of width d and two of his friends are slowly pulling him out using a light rope and two fixed pulleys as shown in the following figure. Show that the force (assumed equal for both the friends) exerted by each friend on the road increases as the man moves up. Find the force when the man is at a depth h.


A force \[\vec{F} = \vec{v} \times \vec{A}\] is exerted on a particle in addition to the force of gravity, where \[\vec{v}\] is the velocity of the particle and \[\vec{A}\] is a constant vector in the horizontal direction. With what minimum speed, a particle of mass m be projected so that it continues to move without being defelected and with a constant velocity? 


In the following figure shows a uniform rod of length 30 cm and mass 3.0 kg. The strings shown in the figure are pulled by constant forces of 20 N and 32 N. Find the force exerted by the 20 cm part of the rod on the 10 cm part. All the surfaces are smooth and the strings and the pulleys are light.


A constant force F = m2g/2 is applied on the block of mass m1 as shown in the following figure. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m1.


In the following figure, m1 = 5 kg, m2 = 2 kg and F = 1 N. Find the acceleration of either block. Describe the motion of m1 if the string breaks but F continues to act.


Find the acceleration of the blocks A and B in the three situations shown in the following figure.


How can Newton's first law of motion be obtained from the second law of motion?


State Newton's second law of motion. Is Newton's first law of motion contained in Newton's second law of motion?


A body of mass 2 kg travels according to the law x(t) = pt + qt2 + rt3 where p = 3 ms−1, q = 4 ms−2 and r = 5 ms−3. The force acting on the body at t = 2 seconds is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×