Advertisements
Advertisements
Question
A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate: The velocity acquired by the body.
Advertisements
Solution
Mass, m = 100 kg
Distance moved, s = 100 m
Initial velocity, u = 0
Because the body moves through a distance of 100 m in 5 s,
Velocity of the body = `"Distance moved"/"time taken"`
Velocity = `100/5`
= 20 m/s
APPEARS IN
RELATED QUESTIONS
When a horse pulls a cart, the force that helps the horse to move forward is the force exerted by
The force of buoyancy exerted by the atmosphere on a balloon is B in the upward direction and remains constant. The force of air resistance on the balloon acts opposite the direction of velocity and is proportional to it. The balloon carries a mass M and is found to fall to the earth's surface with a constant velocity v. How much mass should be removed from the balloon so that it may rise with a constant velocity v?
Consider the situation shown in the following figure. Both the pulleys and the string are light and all the surfaces are frictionless.
- Find the acceleration of the mass M.
- Find the tension in the string.
- Calculate the force exerted by the clamp on the pulley A in the figure.
Calculate the velocity of a body of mass 0.5 kg, when it has a linear momentum of 5 Ns.
An electron of mass 9 × 10−31 kg is moving with a linear velocity of 6 × 107 ms−1. Calculate the linear momentum of electron.
What do you understand by the term momentum?
A stone is thrown vertically upward with a velocity of 9.8 m/s. When will it reach the ground?
A body of mass 2 kg travels according to the law x(t) = pt + qt2 + rt3 where p = 3 ms−1, q = 4 ms−2 and r = 5 ms−3. The force acting on the body at t = 2 seconds is ______.
Why is catching a slow-moving ball easier than catching a fast-moving ball?
What happens when a car brakes to come to a stop?
