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A Force Acts for 10 S on a Stationary Body of Mass 100 Kg, After Which the Force Ceases to Act. the Body Moves Through a Distance of 100 M in the Next 5 S. Calculate : the Acceleration Pro - Physics

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Question

A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate : The acceleration produced by the force

Sum
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Solution

Mass, m = 100 kg

Distance moved, s = 100 m

Initial velocity, u = 0

From Newton's third equation of motion,

v- u2 = 2as.

Or, a = (v2 - u2) /2s.

Or, a = [ (20-  02)/ 2(100) ] ms-2.

Or, a = 2 ms-2.

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Chapter 3: Laws of Motion - Exercise 3 (C) [Page 70]

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Selina Concise Physics [English] Class 9 ICSE
Chapter 3 Laws of Motion
Exercise 3 (C) | Q 7.2 | Page 70

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