Advertisements
Advertisements
Question
A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate : The acceleration produced by the force
Advertisements
Solution
Mass, m = 100 kg
Distance moved, s = 100 m
Initial velocity, u = 0
From Newton's third equation of motion,
v2 - u2 = 2as.
Or, a = (v2 - u2) /2s.
Or, a = [ (202 - 02)/ 2(100) ] ms-2.
Or, a = 2 ms-2.
APPEARS IN
RELATED QUESTIONS
Which force is responsible for the moon revolving round the earth ?
What do you understand by the term 'acceleration due to gravity of earth' ?
A pressure of 10 Pa acts on an area of 3.0 m2. What is the force acting on the area ? What force will be exerted by the application of same pressure if the area is made one-third ?
What will be the weight of a person on earth, who weighs 9N on the moon?
How is the acccelaration due to gravity on the surface of the earth realted to its mass and radius ?
A body is projected vertically upward with an initial velocity u . If acceleartion due to gravity is g , the time for which it remains in air , is :
The free fall of an object is possible only in ______.
Write a short note.
Escape Velocity
The mass and weight of an object on earth are 5 kg and 49 N respectively. What will be their values on the moon? Assume that the acceleration due to gravity on the moon is 1/6th of that on the earth.
When is free fall possible?
