हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

A Stone of Mass M Tied to the End of a String Revolves in a Vertical Circle of Radius R. the Net Forces at the Lowest and Highest Points of the Circle Directed Vertically Downwards Are: [Choose the Correct Alternative]

Advertisements
Advertisements

प्रश्न

A stone of mass tied to the end of a string revolves in a vertical circle of radius R. The net forces at the lowest and highest points of the circle directed vertically downwards are: [Choose the correct alternative]

  Lowest Point Highest Point
a) mg – T1 mg + T2
b) mg + T1 mg – T2
c) `mg + T1 –(m_v_1^2)/R` mg – T2 + (`mv_1^2`)/R
d) `mg – T1 – (mv)/R` mg + T2 + (mv_1^2)/R

 Tand v1 denote the tension and speed at the lowest point. Tand v2 denote corresponding values at the highest point.

Advertisements

उत्तर १

(a)The free body diagram of the stone at the lowest point is shown in the following figure.

According to Newton’s second law of motion, the net force acting on the stone at this point is equal to the centripetal force, i.e.,

`F_"net" = T - mg = (mv_1^2)/R ...(i)`

Where, v1 = Velocity at the lowest point

The free body diagram of the stone at the highest point is shown in the following figure

Using Newton’s second law of motion, we have:

`T + mg = (mv_2^2)/R `...(ii)

Where, v= Velocity at the highest point

It is clear from equations (i) and (ii) that the net force acting at the lowest and the highest points are respectively (T – mg) and (T + mg).

shaalaa.com

उत्तर २

The net force at the lowest point is (mg – T1) and the net force at the highest point is (mg + T2). Therefore, alternative (a) is correct. Since mg and T1 are in mutually opposite directions at lowest point and mg and T2are in same direction at the highest point.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

संबंधित प्रश्न

A rocket with a lift-off mass 20,000 kg is blasted upwards with an initial acceleration of 5.0 m s–2. Calculate the initial thrust (force) of the blast.


A man of mass 70 kg stands on a weighing scale in a lift which is moving

  1. upwards with a uniform speed of 10 m s-1
  2. downwards with a uniform acceleration of 5 m s–2
  3. upwards with a uniform acceleration of 5 m s–2. What would be the readings on the scale in each case?
  4. What would be the reading if the lift mechanism failed and it hurtled down freely under gravity?

A helicopter of mass 1000 kg rises with a vertical acceleration of 15 m s–2. The crew and the passengers weigh 300 kg. Give the magnitude and direction of the

(a) force on the floor by the crew and passengers,

(b) action of the rotor of the helicopter on the surrounding air,

(c) force on the helicopter due to the surrounding air.


An aircraft executes a horizontal loop at a speed of 720 km/h with its wings banked at 15°. What is the radius of the loop?


The rear side of a truck is open and a box of 40 kg mass is placed 5 m away from the open end as shown in Figure. The coefficient of friction between the box and the surface below it is 0.15. On a straight road, the truck starts from rest and accelerates with 2 m s–2. At what distance from the starting point does the box fall off the truck? (Ignore the size of the box).


Both the springs shown in the following figure are unstretched. If the block is displaced by a distance x and released, what will be the initial acceleration?


In a simple Atwood machine, two unequal masses m1 and m2 are connected by a string going over a clamped light smooth pulley. In a typical arrangement (In the following figure), m1 = 300 g and m2 = 600 g. The system is released from rest. (a) Find the distance travelled by the first block in the first two seconds; (b) find the tension in the string; (c) find the force exerted by the clamp on the pulley.


Two balls A and B of masses m and 2 m are in motion with velocities 2v and v, respectively. Compare:

(i) Their inertia.

(ii) Their momentum.

(iii)  The force needed to stop them in the same time.


State the Newton's second law of motion. What information do you get from it?


A force of 10 N acts on a body of mass 2 kg for 3 s, initially at rest. Calculate : Change in momentum of the body.


A bullet of mass 50 g moving with an initial velocity 100 m s-1 strikes a wooden block and comes to rest after penetrating a distance 2 cm in it. Calculate: (i) Initial momentum of the bullet, (ii) Final momentum of the bullet, (iii) Retardation caused by the wooden block and (iv) Resistive force exerted by the wooden block.


A ball is thrown vertically upwards. It returns 6 s later. Calculate the greatest height reached by the ball. (Take g = 10 m s−2)


A pebble is dropped freely in a well from its top. It takes 20 s for the pebble to reach the water surface in the well. Taking g = 10 m s-2 and speed of sound = 330 m s-1. Find : The depth of water surface


A body of mass 200 g is moving with a velocity of 5 ms−1. If the velocity of the body changes to 17 ms−1, calculate the change in linear momentum of the body.


State two factors which determine the momentum of a body.


Prove mathematically F = ma


Use Newton's second law to explain the following:
We always prefer to land on sand instead of hard floor while taking a high jump.


Use Newton's second law to explain the following:
While catching a fast moving ball, we always pull our hands backwards.


Newton’s Second Law corrected the old belief that force is needed to maintain motion. This idea came from the philosopher ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×