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1: GST [Goods and Service Tax]
2: Banking (Recurring Deposit Account)
3: Shares and Dividend
Unit 2. Algebra
4: Linear Inequations (In one variable)
5: Quadratic Equations
6: Solving (simple) Problems (Based on Quadratic Equations)
▶ 7: Ratio and Proportion (Including Properties and Uses)
8: Factorization of Polynomials (Remainder and Factor Theorems)
9: Matrices
10: Arithmetic Progression
11: Geometric Progression
Unit 3. Co-ordinate Geometry
12: Reflection
13: Section Formula and Mid-Point Formula
14: Equation of a Line
Unit 4. Geometry
15: Similarity (With Applications to Maps and Models)
16: Loci (Locus and Its Constructions)
17: Circles
18: Tangents and Intersecting Chords
19: Constructions (Circles)
Unit 5. Mensuration
20: Cylinder, Cone and Sphere
Unit 6. Trigonometry
21: Trigonometrical Identities
22: Height and Distances
Unit 7. Statistics
23: Graphical Representation
24: Measure of Central Tendency (Mean, Median, Quartiles and Mode)
25: Probability
![Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 7 - Ratio and Proportion (Including Properties and Uses) Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 7 - Ratio and Proportion (Including Properties and Uses) - Shaalaa.com](/images/concise-mathematics-english-class-10-icse_6:7eb8c97e7ccc4a1c956f7ac8305d25e3.jpg)
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Solutions for Chapter 7: Ratio and Proportion (Including Properties and Uses)
Below listed, you can find solutions for Chapter 7 of CISCE Selina for Concise Mathematics [English] Class 10 ICSE.
Selina solutions for Concise Mathematics [English] Class 10 ICSE 7 Ratio and Proportion (Including Properties and Uses) Exercise 7 (A) [Page 83]
Multiple Choice Type: Choose the correct answer from the options given below.
If A : B = 7 : 5 and B : C = 7 : 5, then A : C is ______.
25 : 49
49 : 25
1
15 : 14
If `(x^2 - 1)/(x^2 + 1) = 3/5`, the value of x is ______.
`1/2`
2
`± 1/2`
±2
If (2x + 3y) : (3x + 2y) = 4 : 3; then x : y is ______.
6 : 1
2 : 3
1 : 6
3 : 2
Two numbers are in the ratio 5 : 8. If 10 is subtracted from each number, the ratio becomes 4 : 7. The numbers are ______.
80 and 50
50 and 80
25 and 40
40 and 25
The compound ratio of x – y : x + y and (x + y)2 : x2 – y2 is ______.
2 : 1
1 : (x + y)2
1 : 1
1 : 2
If the sub-duplicate ratio of 6x2 : 24y2 is ______.
x : 2y
2x : y
x : y
y : x
If `(m + n)/(m + 3n) = 2/3`, find : `(2n^2)/(3m^2 + mn)`.
If the ratio between 8 and 11 is the same as the ratio of 2x – y to x + 2y, find the value of `(7x)/(9y)`.
Divide Rs. 1290 in to A, B and C such that A is `2/5` of B and B : C = 4 : 3.
A school has 630 students. The ratio of the number of boys to the number of girls is 3 : 2. This ratio changes to 7 : 5 after the admission of 90 new students. Find the number of newly admitted boys.
What quantity must be subtracted from each term of the ratio 9 : 17 to make it equal to 1 : 3?
The work done by (3x − 1) men in (2x + 3) days and the work done by (3x − 4) men in (2x + 1) days are in the ratio 4 : 3. Find the value of x.
If 3A = 4B = 6C, find: A : B : C.
If 2a = 3b and 4b = 5c, find: a : c.
Find the compound ratio of 2 : 3, 9 : 14 and 14 : 27
Find the compound ratio of 2a : 3b, mn : x2 and x : n
If (x + 3) : (4x + 1) is the duplicate ratio of 3 : 5, find the value of x.
If m : n is the duplicate ratio of m + x : n + x; show that x2 = mn.
If (3x – 9) : (5x + 4) is the triplicate ratio of 3 : 4, find the value of x.
Selina solutions for Concise Mathematics [English] Class 10 ICSE 7 Ratio and Proportion (Including Properties and Uses) Exercise 7 (B) [Pages 88 - 89]
Multiple Choice Type: Choose the correct answer from the options given below.
If x, 2, 10 and y are in continued proportion, the values of x and y are respectively:
0.2 and 0.25
0.2 and 50
0.4 and 50
0.4 and 25
If x : y = y : z, then x2 : y2 is ______.
1 : x
x : y
x : z
z : x
The mean proportion between `3 + 2sqrt(2)` and `3 - 2sqrt(2)` is ______.
1
–1
`2sqrt(2)`
3
If 2x, 9 and 18 are in continued proportion, the value of x is ______.
`2 1/4`
`4/9`
1
9
Find the fourth proportional to 1.5, 4.5 and 3.5
Find the fourth proportional to 3a, 6a2 and 2ab2
Find the third proportional to `2 2/3` and 4
Find the third proportional to a – b and a2 – b2
Find the mean proportional between `6 + 3sqrt(3)` and `8 - 4sqrt(3)`
Find the mean proportional between a – b and a3 – a2b
If x + 5 is the mean proportional between x + 2 and x + 9; find the value of x.
If x2, 4 and 9 are in continued proportion, find x.
If y is the mean proportional between x and z; show that xy + yz is the mean proportional between x2 + y2 and y2 + z2.
If q is the mean proportional between p and r, show that: pqr(p + q + r)3 = (pq + qr + rp)3.
If three quantities are in continued proportion, show that the ratio of the first to the third is the duplicate ratio of the first to the second.
(That is, if the three quantities are x, y, and z such that x : y = y : z, prove that \[x : z = x^2 : y^2\].)
Find the third proportional to `x/y + y/x` and `sqrt(x^2 + y^2)`
If p : q = r : s; then show that: mp + nq : q = mr + ns : s.
If p + r = mq and `1/q + 1/s = m/r`; then prove that p : q = r : s.
Selina solutions for Concise Mathematics [English] Class 10 ICSE 7 Ratio and Proportion (Including Properties and Uses) Exercise 7 (C) [Page 96]
Multiple Choice Type: Choose the correct answer from the options given below.
If x + y + z = 0, the value of `x/(y + z)` is ______.
2
`1/2`
1
–1
If a, b, c and d are in proportion, the value of `(8a^2 - 5b^2)/(8c^2 - 5d^2)` is equal to ______.
a2 : b2
a2 : c2
a2 : d2
c2 : d2
`(x + y)/z = (y + z)/x = (z + x)/y` is equal to ______.
0
1
2
–2
If `(x^2 - 4)/(x^2 + 4) = 3/5`, the value of x is ______.
4
± 4
`1/4`
`± 1/4`
If `x/(a + b - c) = y/(b + c - a) = z/(c + a - b) = 5` and a + b + c = 7; the value of x + y + z is ______.
35
`7/5`
`5/7`
42
If a : b = c : d, prove that: 5a + 7b : 5a – 7b = 5c + 7d : 5c – 7d.
If a : b = c : d, prove that: xa + yb : xc + yd = b : d.
If (7a + 8b) (7c – 8d) = (7a – 8b) (7c + 8d); prove that a : b = c : d.
If `x = (6ab)/(a + b)`, find the value of `(x + 3a)/(x - 3a) + (x + 3b)/(x - 3b)`.
If `a = (4sqrt6)/(sqrt2 + sqrt3)`, find the value of `(a + 2sqrt2)/(a - 2sqrt2) + (a + 2sqrt3)/(a - 2sqrt3)`.
If (a + b + c + d) (a – b – c + d) = (a + b – c – d) (a – b + c – d), prove that a : b = c : d.
If `(a - 2b - 3c + 4d)/(a + 2b - 3c - 4d) = (a - 2b + 3c - 4d)/(a + 2b + 3c + 4d)`, show that: 2ad = 3bc.
If a, b and c are in continued proportion, prove that `(a^2 + ab + b^2)/(b^2 + bc + c^2) = a/c`
Using properties of proportion, solve for x:
`(sqrt(x + 5) + sqrt(x - 16))/(sqrt(x + 5) - sqrt(x - 16)) = 7/3`
Using properties of proportion, solve for x:
`(3x + sqrt(9x^2 - 5))/(3x - sqrt(9x^2 - 5)) = 5`
If `x = (sqrt(a + 3b) + sqrt(a - 3b))/(sqrt(a + 3b) - sqrt(a - 3b))`, prove that: 3bx2 – 2ax + 3b = 0.
Using the properties of proportion, solve for x, given. `(x^4 + 1)/(2x^2) = (17)/(8)`.
If `x = (sqrt(m + n) + sqrt(m - n))/(sqrt(m + n) - sqrt(m - n))`, express n in terms of x and m.
If `(x^3 + 3xy^2)/(3x^2y + y^3) = (m^3 + 3mn^2)/(3m^2n + n^3)`, show that nx = my.
13. From the following tables, find the values of ๐, ๐ and ๐:
| Length of cloth bought (in m) | 10 | ๐ | 40 | ๐ |
| Cost of cloth (in โน) | 40 | 100 | ๐ | 180 |
For the following table, find the values of ๐, ๐ and ๐:
| Number of men | 130 | 70 | ๐ | 120 |
| Number of days required to do the same work | ๐ | 39 | 30 | ๐ |
Selina solutions for Concise Mathematics [English] Class 10 ICSE 7 Ratio and Proportion (Including Properties and Uses) TEST YOURSELF [Pages 97 - 99]
Multiple Choice Type: Choose the correct answer from the options given below.
The mean proportional to `sqrt(3) + sqrt(2)` and `sqrt(3) - sqrt(2)` is ______.
`sqrt(5)`
5
1
0
If (a + b) : (a – b) = 13 : 3 ; a : b is ______.
`13/3`
`3/13`
`5/8`
`8/5`
The table, given below, shows the values of x and y, where x is proportional (directly proportional) to y.
| x | A | 24 | 15 |
| y | 12 | B | 20 |
The values of A and B are:
A = 16 and B = 18
A = 32 and B = 9
A = 9 and B = 32
A = 18 and B = 16
If (m + n) : (n − m) = 5 : 2, m : n is ______.
3 : 7
7 : 3
5 : 3
3 : 5
If x = y, the value of (3x + y) : (5x – 3y) is ______.
1 : 2
2 : 1
3 : 2
2 : 3
๐ฅ : ๐ฆ = 3 : 2 and \[(๐ฅ^2 + ๐ฆ^2) : (๐ฅ^2 − ๐ฆ^2)\].
Assertion (A): The value of ratio \[(๐ฅ^2 + ๐ฆ^2) : (๐ฅ^2 − ๐ฆ^2)\] = 13 : 5.
Reason (R): ๐ฅ : ๐ฆ = 3 : 2 \[\Rightarrow \frac{x^{2} + y^{2}}{x^{2} - y^{2}} = \frac{(3k)^{2} + (2k)^{2}}{(3k)^{2} - (2k)^{2}} = \frac{13}{5};\ k \neq 0.\]
A is true, R is false.
A is false, R is true.
Both A and R are true and R is the correct reason for A .
Both A and R are true and R is the incorrect reason for A.
\[\frac{(๐ฅ+๐ฆ)^4}{(๐ฅ−๐ฆ)^4} =\frac{16}1\].
Assertion (A): ๐ฅ : ๐ฆ = 3 : 1.
Reason (R): \[\frac{๐ฅ + ๐ฆ}{๐ฅ−๐ฆ} = 21\] and \[\frac{๐ฅ+๐ฆ+๐ฅ−๐ฆ} {๐ฅ+๐ฆ−๐ฅ+๐ฆ} = \frac{2 + 1}{2−1}.\]
A is true, R is false.
A is false, R is true.
Both A and R are true and R is the correct reason for A .
Both A and R are true and R is the incorrect reason for A .
Two irrational numbers \[\sqrt6\] and \[\sqrt5\].
Statement (1): The mean proportion of \[\sqrt6\] and \[\sqrt5\] is \[\frac{\sqrt6 +\sqrt5}2\].
Statement (2): The mean proportion of two positive real numbers ๐ฅ and ๐ฆ is \[\sqrt{๐ฅ×๐ฆ}\].
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
Numbers ๐,๐ and ๐ are in continued proportion.
Statement (1): (๐ + ๐ + ๐)โข(๐ − ๐ + ๐) = \[๐^2+๐^2+๐^2\]
Statement (2): \[๐^2 = ๐โข๐\] and (๐ +๐ + ๐) โข(๐ − ๐ + ๐) = \[(๐+๐)^2 −๐^2\]
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
If a : b = 3 : 5, find: (10a + 3b) : (5a + 2b)
If 5x + 6y : 8x + 5y = 8 : 9, find x : y.
Find the duplicate ratio of `2sqrt(2) : 3sqrt(5)`
Find the triplicate ratio of 2a : 3b
Find the sub-duplicate ratio of 9x2a4 : 25y6b2
Find the sub-triplicate ratio of 216 : 343
Find the reciprocal ratio of 3 : 5
Find the ratio compounded of the duplicate ratio of 5 : 6, the reciprocal ratio of 25 : 42 and the sub-duplicate ratio of 36 : 49.
Find the value of x, if: (2x + 3) : (5x – 38) is the duplicate ratio of `sqrt(5) : sqrt(6)`.
Find the value of x, if: (2x + 1) : (3x + 13) is the sub-duplicate ratio of 9 : 25.
Find the value of x, if: (3x – 7) : (4x + 3) is the sub-triplicate ratio of 8 : 27.
What quantity must be added to each term of the ratio x : y so that it may become equal to c : d?
A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 84 kg?
If 15(2x2 – y2) = 7xy, find x : y; if x and y both are positive.
Find the fourth proportional to 2xy, x2 and y2.
Find the third proportional to a2 – b2 and a + b.
Find the mean proportional to (x – y) and (x3 – x2y).
Find two numbers such that the mean proportional between them is 14 and third proportional to them is 112.
If x and y be unequal and x : y is the duplicate ratio of x + z and y + z, prove that z is mean proportional between x and y.
If `a/b = c/d`, show that: `(a + b) : (c + d) = sqrt(a^2 + b^2) : sqrt(c^2 + d^2)`
There are 36 members in a student council in a school and the ratio of the number of boys to the number of girls is 3 : 1. How any more girls should be added to the council so that the ratio of the number of boys to the number of girls may be 9 : 5?
If 7x – 15y = 4x + y, find the value of x : y. Hence, use componendo and dividendo to find the values of:
`(9x + 5y)/(9x - 5y)`
If 7x – 15y = 4x + y, find the value of x : y. Hence, use componendo and dividend to find the values of:
`(3x^2 + 2y^2)/(3x^2 - 2y^2)`
If `(4m + 3n)/(4m - 3n) = 7/4`, use properties of proportion to find m : n
If `(4m + 3n)/(4m - 3n) = 7/4`, use properties of proportion to find `(2m^2 - 11n^2)/(2m^2 + 11n^2)`
If x, y, z are in continued proportion, prove that: `(x + y)^2/(y + z)^2 = x/z`.
Given `x = (sqrt(a^2 + b^2) + sqrt(a^2 - b^2))/(sqrt(a^2 + b^2) - sqrt(a^2 - b^2)`. Use componendo and dividendo to prove that: `b^2 = (2a^2x)/(x^2 + 1)`
If `(x^2 + y^2)/(x^2 - y^2) = 2 1/8`, find: `x/y`
If `(x^2 + y^2)/(x^2 - y^2) = 2 1/8`, find: `(x^3 + y^3)/(x^3 - y^3)`
Given `(x^3 + 12x)/(6x^2 + 8) = (y^3 + 27y)/(9y^2 + 27)`. Using componendo and dividendo, find x : y.
If `x/a = y/b = z/c` show that: `x^3/a^3 + y^3/b^3 + z^3/c^3 = (3xyz)/(abc)`.
If b is the mean proportion between a and c, show that: `(a^4 + a^2b^2 + b^4)/(b^4 + b^2c^2 + c^4) = a^2/c^2`.
Find x, if `16((a - x)/(a + x))^3 = (a + x)/(a - x)`.
If ๐ : ๐ : : ๐ : ๐ then prove that: ๐ : (๐ − ๐) : : ๐ : (๐ − ๐).
Using properties of proportion solve:
`(k^5 + x^5)/(x^5 − k^5) = 122/121`
Using properties of proportion solve:
\[ \Rightarrow \frac{x^2-x+1}{x^2+x+1}=\frac{112(1-x)}{104(1+x)} \]
If ๐ฅ ≠ ๐ฆ and \[\frac{๐ฅ^2−๐ฅ+1}{๐ฆ^2−๐ฆ+1} = \frac{๐ฅ^2+๐ฅ+1}{๐ฆ^2+๐ฆ+1}\], prove that ๐ฅโข๐ฆ = 1. Use properties of proportion.
Case-Study Based Questions:
Amit runs a grocery store in a busy neighbourhood market. He stocks two varieties of lentils.
- The premium quality sells at โน 280 per kg.
- The standard quality sells at โน 240 per kg.
Customers in his area are price-conscious, so Amit wants to create a mixture of the two varieties that appears high quality but is also affordable. He decides to sell the mixture at โน 265 per kg.
In what ratio should the โน 240/kg and โน 280/kg varieties be mixed to obtain the mixture costing โน 265 per kg?
In a school chemistry lab, the lab assistant has two bottles of acid solution on his shelf:
- Solution A: 55% acid concentration
- Solution B: 80% acid concentration
The science teacher wants 60% a acid solution for tomorrow's experiment that is to be used by the students.
In what ratio should the 55% solution and the 80% solution be mixed to obtain a 60% acid solution?
Solutions for 7: Ratio and Proportion (Including Properties and Uses)
![Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 7 - Ratio and Proportion (Including Properties and Uses) Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 7 - Ratio and Proportion (Including Properties and Uses) - Shaalaa.com](/images/concise-mathematics-english-class-10-icse_6:7eb8c97e7ccc4a1c956f7ac8305d25e3.jpg)
Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 7 - Ratio and Proportion (Including Properties and Uses)
Shaalaa.com has the CISCE Mathematics Concise Mathematics [English] Class 10 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Selina solutions for Mathematics Concise Mathematics [English] Class 10 ICSE CISCE 7 (Ratio and Proportion (Including Properties and Uses)) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Selina textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.
Concepts covered in Concise Mathematics [English] Class 10 ICSE chapter 7 Ratio and Proportion (Including Properties and Uses) are Ratio, Proportion, Direct Applications of Ratio and Proportion, Ratio in Lowest Terms, All About Ratios: Dividing, Comparing, and Modifying Quantities, Commensurable and Incommensurable Quantities, Composition of Ratios, Concept of Continued Proportion, Properties of Proportion, Ratio, Proportion, Direct Applications of Ratio and Proportion, Ratio in Lowest Terms, All About Ratios: Dividing, Comparing, and Modifying Quantities, Commensurable and Incommensurable Quantities, Composition of Ratios, Concept of Continued Proportion, Properties of Proportion, Ratio, Proportion, Direct Applications of Ratio and Proportion, Ratio in Lowest Terms, All About Ratios: Dividing, Comparing, and Modifying Quantities, Commensurable and Incommensurable Quantities, Composition of Ratios, Concept of Continued Proportion, Properties of Proportion.
Using Selina Concise Mathematics [English] Class 10 ICSE solutions Ratio and Proportion (Including Properties and Uses) exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Selina Solutions are essential questions that can be asked in the final exam. Maximum CISCE Concise Mathematics [English] Class 10 ICSE students prefer Selina Textbook Solutions to score more in exams.
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