Advertisements
Advertisements
Question
If `(x^2 + y^2)/(x^2 - y^2) = 2 1/8`, find: `(x^3 + y^3)/(x^3 - y^3)`
Sum
Advertisements
Solution
`(x^3 + y^3)/(x^3 - y^3)`
= `((x/y)^3 + 1)/((x/y)^3 - 1)`
= `((5/3)^3 + 1)/((5/3)^3 - 1 )`
= `(125/27 + 1)/(125/27 - 1)`
= `((125 + 27)/27)/((125 - 27)/27)`
= `(125 + 27)/(125 - 27)`
= `76/49`
= `1 27/49`
shaalaa.com
Is there an error in this question or solution?
