Advertisements
Advertisements
Question
The work done by (3x − 1) men in (2x + 3) days and the work done by (3x − 4) men in (2x + 1) days are in the ratio 4 : 3. Find the value of x.
Advertisements
Solution
Assuming that all the men do the same amount of work in one day and one day's work of each man = 1 unit
Amount of work done by (3x - 1) men in (2x + 3) days = (3x - 1)(2x + 3),
Amount of work done by (3x - 4) men in (2x + 1) days = (3x - 4)(2x + 1)
According to question:
\[\frac{(3x - 1)(2x + 3)}{(3x - 4)(2x + 1)} = \frac{4}{3}\]
3(3x − 1)(2x + 3) = 4(3x − 4)(2x + 1)
3(6x2 + 9x − 2x − 3) = 4(6x2 + 3x − 8x − 4)
3(6x2 + 7x − 3) = 4(6x2 − 5x − 4)
18x2 + 21x − 9 = 24x2 − 20x − 16
18x2 − 24x2 + 21x + 20x − 9 + 16 = 0
−6x2 + 41x + 7 = 0
6x2 − 41x − 7 = 0
6x2 − 42x + x − 7 = 0
6x(x − 7) + 1(x − 7) = 0
(6x + 1)(x − 7) = 0
6x + 1 = 0 or x − 7 = 0
x = `−1/6` or x = 7
x ≠ `−1/6` as that will make number of men negative which is not possible.
