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Mean (or Average) Value of Alternating Current (or Voltage)

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Estimated time: 5 minutes
CISCE: Class 12

Introduction

The mean (or average) value of alternating current is the arithmetic average of all its instantaneous values over a given time interval.

Analogy: Imagine walking 5 steps forward and then 5 steps back. Your net displacement is zero — similar to AC over a full cycle. But if you only consider the forward walk (half-cycle), your average step count is meaningful.

In AC circuits:

  • Current changes direction periodically.
  • Over a full cycle, positive and negative halves cancel → mean = 0.
  • Over a half-cycle, we get a finite, useful average → mean = 0.637 × peak value.
CISCE: Class 12

Derivation: Over One Full Cycle (0 to T)

Given:

  • I = I0 sin ⁡ωt

Mean value over time T:

  • Iavg = \[\frac{1}{T}\int_0^TIdt=\frac{I_0}{T}\int_0^T\sin\omega tdt\]

Solving:

  • \[\frac{I_0}{T}\left[-\frac{\cos\omega t}{\omega}\right]_0^T=\frac{I_0}{\omega T}(-\cos\omega T+\cos0)\]

Since ωT = 2π:

  • \[\frac{I_0}{2\pi}(-\cos2\pi+\cos0)=\frac{I_0}{2\pi}(-1+1)=0\]

Conclusion: Mean value over full cycle = 0

CISCE: Class 12

Derivation: Over Half Cycle (0 to T/2)

  • \[I_m=\frac{1}{T/2}\int_0^{T/2}Idt=\frac{2}{T}\int_0^{T/2}I_0\sin\omega tdt\]

Substitute T = \[\frac {2π}{ω}\]:

  • \[I_m=\frac{2\omega}{2\pi}\int_0^{\pi/\omega}I_0\sin\omega tdt=\frac{\omega I_0}{\pi}\left[-\frac{\cos\omega t}{\omega}\right]_0^{\pi/\omega}\]
  • \[\frac{I_0}{\pi}(-\cos\pi+\cos0)=\frac{I_0}{\pi}(-(-1)+1)=\frac{2I_0}{\pi}\]
  • \[{I_m=\frac{2}{\pi}I_0=0.637I_0}\]

Conclusion: Mean value over half-cycle = 63.7% of peak value

CISCE: Class 12

Physical Interpretation & Real-Life Example

If peak current I0 = 10A, then:
→ Mean current over half-cycle = 0.637 × 10 = 6.37 A

This is the DC-equivalent average you’d measure if you “smoothed” only the positive half of the AC wave (as in half-wave rectifiers).

Real-Life Application:

  • Half-Wave Rectifier: Converts AC to pulsating DC. The output’s average voltage is Vm = 0.637 V0.
  • Galvanometer in AC Circuit: Shows no deflection because the needle can’t follow 50Hz reversals → net average torque = 0.
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