Electric Field - Electric Field Intensity Due to a Point-Charge

Consider two identical point charges located at points (0, 0) and (a, 0).

Is there a point on the line joining them at which the electric field is zero?

An isolated point charge particle produces an electric field `vecE` at a point 3 m away from it. The distance of the point at which the field is `vecE/4` will be ______.

Why must electrostatic field at the surface of a charged conductor be normal to the surface at every point? Give reason?

Consider two identical point charges located at points (0, 0) and (a, 0).

Is there a point on the line joining them at which the electric potential is zero?

Let there be a spherically symmetric charge distribution with charge density varying as `rho("r") = rho_0(5/4 - "r"/"R")` upto r = R, and `rho("r") = 0` for r > R, where r is the distance from the origin. The electric field at a distance r(r < R) from the origin is given by _________.

A charge is distributed uniformly over a ring of radius 'a'. Obtain an expression for the electric intensity E at a point on the axis of the ring. Hence, show that for points at large distance from the ring, it behaves like a point charge.

Two equal point charges of the same sign are fixed on the y-axis, on either side of the origin equidistant from it, with the distance between them d. A third charge moves along the x-axis. The distance of the third charge from either of the two fixed charges when force on the third charge is maximum will be ______ cm.

[d = 10 cm]

What is the function of uniform radial field and how is it produced?