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Capacitance of an Isolated Spherical Conductor

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Estimated time: 5 minutes
CISCE: Class 12

Derivation: Capacitance of an Isolated Spherical Conductor

Setup: Consider an isolated conducting sphere of radius a, carrying charge +q, placed in vacuum/air. Charge spreads uniformly over its outer surface.

Step 1: Potential at the surface
Treating the sphere as equivalent to a point charge q at its center (for external points):

  • V = \[\frac{1}{4\pi\varepsilon_0}\cdot\frac{q}{a}\]

Step 2: Apply the capacitance definition

  • C = \[\frac {q}{V}\] = \[\frac{q}{\frac{1}{4\pi\varepsilon_0}\cdot\frac{q}{a}}\]

Step 3: Simplify

  • C = 4πε0a

Result: Capacitance is directly proportional to the radius of the sphere: C ∝ a.

CISCE: Class 12

Effect of Dielectric Medium

If the sphere is surrounded by a medium of dielectric constant K instead of vacuum:

CK = 4πε0Ka
  • C ∝ K — capacitance increases with dielectric constant.
  • Capacitance is minimum in vacuum/air (K = 1) and increases in any denser dielectric medium.
  • Graphs of C vs a and C vs K are both straight lines through the origin.
CISCE: Class 12

Factors Affecting Capacitance of a Sphere

  • Size (radius): Larger radius → larger surface area → higher capacitance.
  • Medium: Higher dielectric constant → higher capacitance.
  • Presence of nearby conductors: Can alter effective capacitance (not applicable for a truly isolated sphere, but relevant conceptually).
CISCE: Class 12

Real-Life Analogy

Think of capacitance like the capacity of a water tank: a wider tank (larger radius) can hold more water (charge) for the same water level (potential). Similarly, a bigger sphere stores more charge for the same potential.

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