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Solve the following. A hot air balloon has a volume of 2800 m3 at 99° C. What is the volume if the air cools to 80° C? - Chemistry

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Question

Solve the following.

A hot air balloon has a volume of 2800 m3 at 99°C. What is the volume if the air cools to 80°C?

Numerical
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Solution

Given:
V1 = Initial volume = 2800 m3,
T1 = Initial temperature = 99°C = 99 + 273.15 = 372.15 K,
T2 = Final temperature = 80°C = 80 + 273.15 K = 353.15 K

To find: V2 = Final volume

Formula: `"V"_1/"T"_1="V"_2/"T"_2` (at constant n and P)

Calculation:

According to Charles’ law,

`"V"_1/"T"_1="V"_2/"T"_2` (at constant n and P)

∴ V2 = `("V"_1"T"_2)/"T"_1=(2800xx353.15)/372.15` = 2657 m3

The volume of the balloon when the air cools to 80°C is 2657 m3

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Chapter 10: States of Matter - Exercises [Page 159]

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Balbharati Chemistry [English] Standard 11 Maharashtra State Board
Chapter 10 States of Matter
Exercises | Q 5. (D) | Page 159

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