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Question
Solve the following.
The volume of a given mass of a gas at 0°C is 2 dm3. Calculate the new volume of the gas at constant pressure when the temperature is decreased by 10°C.
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Solution
Given:
T1 = Initial temperature = 0°C = 0 + 273.15 = 273.15 K,
V1 = Initial volume = 2 dm3
T2 = Final temperature = 273.15 K − 10 = 263.15 K
To find: V2 = Final volume
Formula: `"V"_1/"T"_1="V"_2/"T"_2` (at constant n and P)
Calculation:
According to Charles’ law,
`"V"_1/"T"_1="V"_2/"T"_2` (at constant n and P)
∴ V2 = `("V"_1"T"_2)/"T"_1=(2xx263.15)/273.15` = 1.927 dm3
The new volume of a given mass of gas is 1.927 dm3
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