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Calculate the rise of water inside a clean glass capillary tube of radius 0.1 mm, when immersed in water of surface tension 7 × 10-2 N/m. The angle of contact between water and glass is zero,

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Question

Calculate the rise of water inside a clean glass capillary tube of radius 0.1 mm, when immersed in water of surface tension 7 × 10-2 N/m. The angle of contact between water and glass is zero, the density of water = 1000 kg/m3, g = 9.8 m/s2.

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Solution 1

Given :

▪ Radius of capillary tube = 0.1 mm

▪ Surface tension of water = 7×10-2 N/m 

▪ Angle of contact = 0°

▪ Density of water = 1000 kg/m

▪ Acceleration due to gravity = 9.8 m/s

To find:

▪ Height of water column inside the capillary tube.

Formula:

When a capillary tube of radius 'r' is dipped in a liquid of density ρ and surface tension T, the liquid rises or falls through a distance,

H = `(2"T" "cos" theta)/(rho "gr")`

H = `(2 xx 7 xx 10^-2 xx "cos" theta)/(1000 xx 9.8 xx 0.1 xx 10^-3)`

H = 0.142 m

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Solution 2

Given:

r = 0.1 mm = 10−4 m,

T = 7 × 10−2 N/m,

θ = 0°,

ρ = 1000 kg/m3, g = 9.8 m/s2  

To find: Height of capillary rise (h)

Formula: h = `(2Tcosθ)/(rρg)` 

Calculation: From formula,

h = `(2 xx (7 xx 10^-2) xx cos0^circ)/(10^-4 xx 10^3 xx 9.8)`

= `(14 xx 10^-1)/(9.8)`

= `1/7`

= 0.1429 m 

The rise of water inside the glass capillary is 0.1429 m.

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Chapter 2: Mechanical Properties of Fluids - Exercises [Page 55]

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Balbharati Physics [English] Standard 12 Maharashtra State Board
Chapter 2 Mechanical Properties of Fluids
Exercises | Q 18 | Page 55
SCERT Maharashtra Physics [English] 12 Standard HSC
Chapter 2 Mechanical Properties of fluids
Short Answer I | Q 4

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