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A man of mass 70 kg stands on a weighing scale in a lift which is moving upwards with a uniform speed of 10 m s-1 downwards with a uniform acceleration of hurtled down freely under gravity? - Physics

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Question

A man of mass 70 kg stands on a weighing scale in a lift which is moving

  1. upwards with a uniform speed of 10 m s-1
  2. downwards with a uniform acceleration of 5 m s–2
  3. upwards with a uniform acceleration of 5 m s–2. What would be the readings on the scale in each case?
  4. What would be the reading if the lift mechanism failed and it hurtled down freely under gravity?
Numerical
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Solution

Here, m = 70 kg, g = 10 m/s2

In each instance, the weighing machine measures the reaction R, which represents the apparent weight.

(a) When the lift moves upwards with a uniform speed, acceleration a = 0.
R = mg = 70 x 10 = 700 N

(b) When the lift moves downward with a = 5 ms-2

R = m (g - a) = 70 (10 - 5) = 350 N

(c) When the lift moves upwards with a = 5 ms-2

R = m (g + a) = 70 (10 + 5) = 1050 N

(d) If the lift were to come down freely under gravity, downward acceleration. a = g

∴ R = m (g - a) = m (g - g) = zero.

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Chapter 4: Laws of Motion - EXERCISES [Page 69]

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NCERT Physics [English] Class 11
Chapter 4 Laws of Motion
EXERCISES | Q 4.13 | Page 69

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