English
Karnataka Board PUCPUC Science Class 11

Car Moving at 40 Km/Hr is to Be Stopped by Applying Brakes in the Next 4 M. If the Car Weighs 2000 Kg, What Average Force Must Be Applied

Advertisements
Advertisements

Question

 car moving at 40 km/hr is to be stopped by applying brakes in the next 4 m. If the car weighs 2000 kg, what average force must be applied to stop it?

Sum
Advertisements

Solution

Given:
Initial speed of the car, u = 40 km/hr
\[= \frac{4000}{3600} = 11 . 11 m/s\]
Final speed of the car, v = 0
Mass of the car, m = 2000 kg
Distance to be travelled by the car before coming to rest, s = 4m
Acceleration, 
\[a = \frac{v^2 - u^2}{2s}\]
\[\Rightarrow a = \frac{0^2 - \left( 11 . 11 \right)^2}{2 \times 4} = \frac{- 123 . 43}{8} = - 15 . 42 m/ s^2\]
∴ Average force to be applied to stop the car, F = ma
⇒ F = 2000 × 15.42 ≈ 3.1 × 104 N

shaalaa.com
  Is there an error in this question or solution?
Chapter 5: Newton's Laws of Motion - Exercise [Page 79]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 5 Newton's Laws of Motion
Exercise | Q 2 | Page 79

RELATED QUESTIONS

Explain why a cricketer moves his hands backwards while holding a catch.


A block of mass 15 kg is placed on a long trolley. The coefficient of static friction between the block and the trolley is 0.18. The trolley accelerates from rest with 0.5 ms–2 for 20 s and then moves with uniform velocity. Discuss the motion of the block as viewed by (a) a stationary observer on the ground, (b) an observer moving with the trolley.


A car accelerates on a horizontal road due to the force exerted by.


Two blocks A and B of mass mA and mB , respectively, are kept in contact on a frictionless table. The experimenter pushes block A from behind, so that the blocks accelerate. If block A exerts force F on block B, what is the force exerted by the experimenter on block A?


A person is standing on a weighing machine placed on the floor of an elevator. The elevator starts going up with some acceleration, moves with uniform velocity for a while and finally decelerates to stop. The maximum and the minimum weights recorded are 72 kg and 60 kg, respectively. Assuming that the magnitudes of acceleration and deceleration are the same, find (a) the true weight of the person and (b) the magnitude of the acceleration. Take g = 9.9 m/s2.


A force \[\vec{F} = \vec{v} \times \vec{A}\] is exerted on a particle in addition to the force of gravity, where \[\vec{v}\] is the velocity of the particle and \[\vec{A}\] is a constant vector in the horizontal direction. With what minimum speed, a particle of mass m be projected so that it continues to move without being defelected and with a constant velocity? 


Consider the Atwood machine of the previous problem. The larger mass is stopped for a moment, 2.0 s after the system is set into motion. Find the time that elapses before the string is tight again.


A constant force F = m2g/2 is applied on the block of mass m1 as shown in the following figure. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m1.


The correct form of Newton's second law is : 


The unit of linear momentum is :


Calculate the magnitude of force which when applied on a body of mass 0.5 kg produces an acceleration of 5 m s-2.


A bullet of mass 50 g moving with an initial velocity 100 m s-1 strikes a wooden block and comes to rest after penetrating a distance 2 cm in it. Calculate: (i) Initial momentum of the bullet, (ii) Final momentum of the bullet, (iii) Retardation caused by the wooden block and (iv) Resistive force exerted by the wooden block.


Calculate the velocity of a body of mass 0.5 kg, when it has a linear momentum of 5 Ns.


Prove mathematically F = ma


Multiple Choice Question. Select the correct option.

Which of the following are vector quantities?


What do you mean by an impulsive force?


The motion of a particle of mass m is given by x = 0 for t < 0 s, x(t) = A sin 4 pt for 0 < t < (1/4) s (A > o), and x = 0 for t > (1/4) s. Which of the following statements is true?

  1. The force at t = (1/8) s on the particle is – 16π2 Am.
  2. The particle is acted upon by on impulse of magnitude 4π2 A m at t = 0 s and t = (1/4) s.
  3. The particle is not acted upon by any force.
  4. The particle is not acted upon by a constant force.
  5. There is no impulse acting on the particle.

Newton’s Second Law corrected the old belief that force is needed to maintain motion. This idea came from the philosopher ______.


As shown in figure, a 70 kg garden roller is pushed with a force of F = 200 N at an angle of 30° with horizontal. The normal reaction on the roller is: (Given: g = 10 ms−2)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×