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A Pebble is Thrown Vertically Upwards with a Speed of 20 M S-1. How High Will It Be After 2 S? (Take G = 10 M S-2)

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Question

A pebble is thrown vertically upwards with a speed of 20 m s-1. How high will it be after 2 s? (Take g = 10 m s-2)

Sum
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Solution

Initial velocity, u = 20 m/s

Time, t = 2s

g = 10 m/s2

Maximum height reached in 2s, H = (1/2) gt2

Or, H = (1/2) (10) (2) 2

Or, H = 20 m

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Chapter 3: Laws of Motion - Exercise 3 (E) [Page 81]

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Selina Concise Physics [English] Class 9 ICSE
Chapter 3 Laws of Motion
Exercise 3 (E) | Q 14 | Page 81

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