Advertisements
Advertisements
Question
A pebble is thrown vertically upwards with a speed of 20 m s-1. How high will it be after 2 s? (Take g = 10 m s-2)
Advertisements
Solution
Initial velocity, u = 20 m/s
Time, t = 2s
g = 10 m/s2
Maximum height reached in 2s, H = (1/2) gt2
Or, H = (1/2) (10) (2) 2
Or, H = 20 m
APPEARS IN
RELATED QUESTIONS
When a horse pulls a cart, the force that helps the horse to move forward is the force exerted by
A man has fallen into a ditch of width d and two of his friends are slowly pulling him out using a light rope and two fixed pulleys as shown in the following figure. Show that the force (assumed equal for both the friends) exerted by each friend on the road increases as the man moves up. Find the force when the man is at a depth h.
In the previous problem, suppose m2 = 2.0 kg and m3 = 3.0 kg. What should be the mass m, so that it remains at rest?
State Newton's second law of motion. Under what condition does it take the form F = ma?
A body of mass 5 kg is moving with velocity 2 m s-1. Calculate its linear momentum.
ame the law of motion which gives the definition of force.
Name the physical entity used for quantifying the motion of a body.
A ball is thrown upward and reaches a maximum height of 19.6 m. Find its initial speed?
A cricket ball of mass 150 g has an initial velocity `u = (3hati + 4hatj)` m s−1 and a final velocity `v = - (3hati + 4hatj)` m s−1 after being hit. The change in momentum (final momentum-initial momentum) is (in kg m s1)
A hockey player is moving northward and suddenly turns westward with the same speed to avoid an opponent. The force that acts on the player is ______.
