English
Karnataka Board PUCPUC Science Class 11

A Spy Jumps from an Airplane with His Parachute. the Spy Accelerates Downward for Some Time When the Parachute Opens. the Acceleration is Suddenly Checked and the Spy Slowly Falls to the

Advertisements
Advertisements

Question

A spy jumps from an airplane with his parachute. The spy accelerates downward for some time when the parachute opens. The acceleration is suddenly checked and the spy slowly falls to the ground. Explain the action of the parachute in checking the acceleration.

Short/Brief Note
Advertisements

Solution

Air applies a velocity-dependent force on the parachute in upward direction when the parachute opens. This force opposes the gravitational force acting on the spy. Hence, the net force in the downward direction decreases and the spy decelerates.

shaalaa.com
  Is there an error in this question or solution?
Chapter 5: Newton's Laws of Motion - short answers [Page 77]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 5 Newton's Laws of Motion
short answers | Q 13 | Page 77

RELATED QUESTIONS

A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 ms–1. How long does the body take to stop?


A block of mass 15 kg is placed on a long trolley. The coefficient of static friction between the block and the trolley is 0.18. The trolley accelerates from rest with 0.5 ms–2 for 20 s and then moves with uniform velocity. Discuss the motion of the block as viewed by (a) a stationary observer on the ground, (b) an observer moving with the trolley.


A person says that he measured the acceleration of a particle to be non-zero even though no force was acting on the particle.


A particle of mass 50 g moves in a straight line. The variation of speed with time is shown in the following figure. Find the force acting on the particle at t = 2, 4 and 6 seconds.


A small block B is placed on another block A of mass 5 kg and length 20 cm. Initially, the block B is near the right end of block A (In the following Figure). A constant horizontal force of 10 N is applied to the block A. All the surfaces are assumed frictionless. Find the time that elapses before block B separates from A.


A body of mass m moving with a velocity v is acted upon by a force. Write an expression for change in momentum in each of the following cases: (i) When v << c, (ii) When v → c and (iii) When v << c but m does not remain constant. Here, c is the speed of light.


Show that the rate of change of momentum = mass × acceleration. Under what condition does this relation hold?


Use Newton's second law of motion to explain the following instance : 

A cricketer pulls his hands back while catching a fast moving cricket ball .


The unit of linear momentum is :


A body of mass 5 kg is moving with velocity 2 m s-1. Calculate its linear momentum.


A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate : The magnitude of the force


A bullet of mass 50 g moving with an initial velocity 100 m s-1 strikes a wooden block and comes to rest after penetrating a distance 2 cm in it. Calculate: (i) Initial momentum of the bullet, (ii) Final momentum of the bullet, (iii) Retardation caused by the wooden block and (iv) Resistive force exerted by the wooden block.


Multiple Choice Question. Select the correct option.

The impulse of a body is equal to:


Which of the following has the largest inertia?


Why is it advantageous to turn before taking a long jump?


Use Newton's second law to explain the following:
While catching a fast moving ball, we always pull our hands backwards.


A ball is thrown vertically downward with an initial velocity of 10 m/s. What is its speed 1 s later and 2 s later?


What do you mean by the conservation of momentum? Briefly, explain the collision between two bodies and the conservation of momentum.


The motion of a particle of mass m is given by x = 0 for t < 0 s, x(t) = A sin 4 pt for 0 < t < (1/4) s (A > o), and x = 0 for t > (1/4) s. Which of the following statements is true?

  1. The force at t = (1/8) s on the particle is – 16π2 Am.
  2. The particle is acted upon by on impulse of magnitude 4π2 A m at t = 0 s and t = (1/4) s.
  3. The particle is not acted upon by any force.
  4. The particle is not acted upon by a constant force.
  5. There is no impulse acting on the particle.

According to Newton's Second Law of Motion, what quantity is directly proportional to the applied force?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×