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Question
Consider the situation shown in the following figure. Both the pulleys and the string are light and all the surfaces are frictionless.
- Find the acceleration of the mass M.
- Find the tension in the string.
- Calculate the force exerted by the clamp on the pulley A in the figure.

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Solution
Let the acceleration of mass M be a.
So, the acceleration of mass 2M will be \[\frac{a}{2}\]

(a)

2M(a/2) − 2T = 0
⇒ Ma = 2T
T + Ma − Mg = 0
\[\Rightarrow \frac{Ma}{2} + Ma = Mg \]
\[ \Rightarrow 3Ma = 2Mg\]
\[ \Rightarrow a = \frac{2g}{3}\]
(b) Tension,

\[T = \frac{Ma}{2} = \frac{M}{2} \times \frac{2g}{3} = \frac{Mg}{3}\]
(c)

Let T' = resultant of tensions
\[\therefore T' = \sqrt{T^2 + T^2} = \sqrt{2}T\]
\[ \therefore T' = \sqrt{2}T = \frac{\sqrt{2}Mg}{3}\]
\[\text{Again, }\tan\theta = \frac{T}{T} = 1\]
\[ \Rightarrow \theta = 45^\circ\]
So, it is `(sqrt2"Mg")/3` at an angle of 45° with the horizontal.
That is the force exerted by the clamp.
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