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A combination of lenses for a camera contains two converging lenses of focal lengths 20 cm and 40 cm and a diverging lens of focal length 50 cm. Find the power and focal length of the combination.

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Question

A combination of lenses for a camera contains two converging lenses of focal lengths 20 cm and 40 cm and a diverging lens of focal length 50 cm. Find the power and focal length of the combination.

Numerical
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Solution

Focal length (f1) of the 1st converging lens = 20 cm = 0.2 m

Focal length (f2) of the 2nd converging lens = 40 cm = 0.4 m

Focal length (f3) of the diverging lens = −50 cm = −0.5 m (negative sign due to sign convention)

Power  = `1/"Focal length of lens (in metre)"`

Power (P1) of 1st lens = `1/0.2` = 5 D 

Power (P2) of 2nd lens = `1/0.4` = 2.5 D

Power (P3) of diverging  lens = `1/0.5` = −2 D

Net power of the combination = P1 + P2 + P3

= 5 + 2.5 + (−2)

= 7.5 − 2

= 5.5 D 

Net focal length of the combination = `1/"Net power"`

= `1/5.5`

= 0.1818 m

= 18.18 cm

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Chapter 5: Refraction of Light through Lenses - EXERCISE [Page 136]

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Lakhmir Singh Physics [English] Class 10 ICSE
Chapter 5 Refraction of Light through Lenses
EXERCISE | Q 11. | Page 136
Lakhmir Singh Physics Part 1 [English] Class 10
Chapter 2 Refraction of Light
Exercise 7 | Q 29. (c) | Page 132

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