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Question
For a lens immersed in a medium of refractive index \[n_1\], the power is related to the focal length by:
Options
\[P = \frac{n_1}{f}\]
\[P = \frac{n_2}{f}\]
\[P = n_1 f\]
\[P = \frac{1}{n_1 f}\]
MCQ
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Solution
When the lens is immersed in a medium of refractive index \[n_1\], the power is \[P = \frac{n_1}{f}\]. This is the power of the lens in that surrounding medium.
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