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A Batsman Deflects a Ball by an Angle of 45° Without Changing Its Initial Speed Which is Equal to 54 Km/H. What is the Impulse Imparted to the Ball? (Mass of the Ball is 0.15 Kg.)

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Question

A batsman deflects a ball by an angle of 45° without changing its initial speed which is equal to 54 km/h. What is the impulse imparted to the ball? (Mass of the ball is 0.15 kg.)

Numerical
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Solution

The given situation can be represented as shown in the following figure.

Where,

AO = Incident path of the ball

OB = Path followed by the ball after deflection

∠AOB = Angle between the incident and deflected paths of the ball = 45°

∠AOP = ∠BOP = 22.5° = θ

Initial and final velocities of the ball = v

Initial velocity's horizontal component = vcos θ along RO

Initial velocity's vertical component = vsin θ along PO

Final velocity's horizontal component = vcos θ along OS

Final velocity's vertical component = vsin θ along OP

The horizontal velocity components remain unchanged. The vertical velocity components are directed oppositely.

∴Impulse imparted to the ball = Change in the linear momentum of the ball

`= mvcostheta - (- mvcos theta)`

`= 2mvcos theta`

Mass of the ball, m = 0.15 kg

Velocity of the ball, v = 54 km/h = 15 m/s

∴ Impulse = 2 × 0.15 × 15 cos 22.5° = 4.16 kg m/s

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Chapter 4: Laws of Motion - EXERCISES [Page 70]

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NCERT Physics Part 1 and 2 [English] Class 11
Chapter 4 Laws of Motion
EXERCISES | Q 4.20 | Page 70

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