Advertisements
Advertisements
Question
A ball is thrown vertically upwards. It returns 6 s later. Calculate the greatest height reached by the ball. (Take g = 10 m s−2)
Advertisements
Solution
Given:
Total time of journey = 6 s
g = 10 m/s2
Let h be the greatest height.
From the equation of motion,
`h = ut + 1/2 g t^2`
(we consider motion of ball from highest point to the ground.)
Since the total time for journey of the ball in air = 6 s.
Therefore, time for reaching maximum height = `6/2` = 3 s
For ascent, initial velocity, u = 0
Substituting the values in the formula, we get,
`h = (0 xx 3) + (1/2 xx 10 xx 3^2)`
h = 0 + (5 × 9)
h = 45 m
Hence, greatest height reached by the ball = 45 m
APPEARS IN
RELATED QUESTIONS
The below figure shows the position-time graph of a particle of mass 4 kg.
- What is the force on the particle for t < 0, t > 4 s, 0 < t < 4 s?
- What is the impulse at t = 0 and t = 4 s? (Consider one-dimensional motion only.)
You are travelling in a car. The driver suddenly applies the brakes and you are pushed forward. Why does this happen?
Suppose you are running fast in a field and suddenly find a snake in front of you. You stop quickly. Which force is responsible for your deceleration?
A constant force F = m2g/2 is applied on the block of mass m1 as shown in the following figure. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m1.
Define linear momentum and state its S.I. unit.
A body of mass 200 g is moving with a velocity of 5 ms−1. If the velocity of the body changes to 17 ms−1, calculate the change in linear momentum of the body.
State two factors which determine the momentum of a body.
What do you mean by linear momentum of a body?
What do you mean by an impulsive force?
What do you mean by the conservation of momentum? Briefly, explain the collision between two bodies and the conservation of momentum.
