English
Karnataka Board PUCPUC Science Class 11

Suppose You Are Running Fast in a Field and Suddenly Find a Snake in Front of You. You Stop Quickly. Which Force is Responsible for Your Deceleration? - Physics

Advertisements
Advertisements

Question

Suppose you are running fast in a field and suddenly find a snake in front of you. You stop quickly. Which force is responsible for your deceleration?

Short/Brief Note
Advertisements

Solution

The force of friction acting between my feet and ground is responsible for my deceleration.

shaalaa.com
  Is there an error in this question or solution?
Chapter 5: Newton's Laws of Motion - short answers [Page 77]

APPEARS IN

HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 5 Newton's Laws of Motion
short answers | Q 10 | Page 77

RELATED QUESTIONS

A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 ms–1. How long does the body take to stop?


A batsman deflects a ball by an angle of 45° without changing its initial speed which is equal to 54 km/h. What is the impulse imparted to the ball? (Mass of the ball is 0.15 kg.)


The figure shows the displacement of a particle going along the X-axis as a function of time. The force acting on the particle is zero in the region


(a) AB
(b) BC
(c) CD
(d) DE


Suppose the ceiling in the previous problem is that of an elevator which is going up with an acceleration of 2.0 m/s2. Find the elongation.


In the following figure shows a uniform rod of length 30 cm and mass 3.0 kg. The strings shown in the figure are pulled by constant forces of 20 N and 32 N. Find the force exerted by the 20 cm part of the rod on the 10 cm part. All the surfaces are smooth and the strings and the pulleys are light.


A constant force F = m2g/2 is applied on the block of mass m1 as shown in the following figure. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m1.


Consider the situation shown in the following figure. Both the pulleys and the string are light and all the surfaces are frictionless.

  1. Find the acceleration of the mass M.
  2. Find the tension in the string.
  3. Calculate the force exerted by the clamp on the pulley A in the figure.


Use Newton's second law of motion to explain the following instance :
An athlete prefers to land on sand instead of hard floor while taking a high jump .


A force of 10 N acts on a body of mass 2 kg for 3 s, initially at rest. Calculate : The velocity acquired by the body


A force of 10 N acts on a body of mass 2 kg for 3 s, initially at rest. Calculate : Change in momentum of the body.


A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate : The magnitude of the force


A car is moving with a uniform velocity 30 ms-1. It is stopped in 2 s by applying a force of 1500 N through its brakes. Calculate the following values : The change in momentum of car.


Calculate the velocity of a body of mass 0.5 kg, when it has a linear momentum of 5 Ns.


Multiple Choice Question. Select the correct option.

A force acts on a body of mass 3 kg such that its velocity changes from 4 ms−1 to 10 ms−1. The change in momentum of the body is


Which of the following has the largest inertia?


Why is it advantageous to turn before taking a long jump?


A stone is dropped from a cliff 98 m high.
How long will it take to fall to the foot of the cliff?


A stone is dropped from a cliff 98 m high.
What will be its speed when it strikes the ground?


A cricket ball of mass 150 g has an initial velocity `u = (3hati + 4hatj)` m s−1 and a final velocity `v = - (3hati + 4hatj)` m s−1 after being hit. The change in momentum (final momentum-initial momentum) is (in kg m s1)


The motion of a particle of mass m is given by x = 0 for t < 0 s, x(t) = A sin 4 pt for 0 < t < (1/4) s (A > o), and x = 0 for t > (1/4) s. Which of the following statements is true?

  1. The force at t = (1/8) s on the particle is – 16π2 Am.
  2. The particle is acted upon by on impulse of magnitude 4π2 A m at t = 0 s and t = (1/4) s.
  3. The particle is not acted upon by any force.
  4. The particle is not acted upon by a constant force.
  5. There is no impulse acting on the particle.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×