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Conversion of a Galvanometer in Ammeter

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Estimated time: 5 minutes
CISCE: Class 12

Introduction

An ammeter is a device used to measure electric current, and it is always connected in series in a circuit. For a device to serve as an ideal ammeter, it must offer zero resistance, so that it does not alter the current it is measuring.

A galvanometer, although capable of detecting current, cannot be used directly as an ammeter because it possesses appreciable internal resistance. Connecting it directly into a circuit would reduce the current flowing through it, giving inaccurate readings.

CISCE: Class 12

Shunt Is Needed

To convert a galvanometer into an ammeter capable of measuring larger currents, a low-resistance shunt (S) is connected in parallel with the galvanometer coil (resistance G).

  • The galvanometer carries only its safe full-scale current Ig
  • The remaining current (I − Ig) passes through the shunt
  • This protects the galvanometer while allowing measurement of large currents
CISCE: Class 12

Derivation of Shunt Resistance

Since G and S are in parallel, the potential difference across both is equal:

IgG = (I − Ig)S

Rearranging for shunt resistance:

S = \[\frac {I_gG}{I−I_g}\]

Effective Resistance of the Ammeter: RA = \[\frac {GS}{G+S}\]

CISCE: Class 12

Example

A galvanometer of resistance G = 15 Ω gives full-scale deflection for Ig = 4 mA. Convert it into an ammeter of range I = 6 A.

Solution:

S = \[\frac{I_gG}{I-I_g}=\frac{(4\times10^{-3})(15)}{6-4\times10^{-3}}\]
S ≈ \[\frac {0.06}{5.996}\] ≈ 0.01 Ω

Correct Answer: S ≈ 0.01 Ω

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