हिंदी

Mechanism of Flow of Electrons Through the Metal Conductors

Advertisements

Topics

Estimated time: 6 minutes
CISCE: Class 12

Introduction

When you switch on a bulb, light appears almost instantly — yet individual electrons in the copper wire move incredibly slowly (a few cm per second). This topic explains that apparent contradiction.

A metal conductor contains a huge number of free (valence) electrons that are not bound to any particular atom. Understanding how these electrons behave — with and without an applied electric field — is the foundation for Ohm's Law and resistivity.

CISCE: Class 12

Behaviour Without an Electric Field

  • Free electrons move randomly in all directions due to thermal energy.
  • Their motion resembles a "gas" of particles — hence the term electron gas.
  • Because motion is random, the net displacement over time is zero → no current flows.
  • Collisions occur continuously with vibrating lattice ions, impurities, and grain boundaries, and these collisions are the microscopic origin of electrical resistance.
CISCE: Class 12

Behaviour With an Applied Electric Field

  • When a potential difference V is applied across a conductor of length l, a uniform electric field E = V/l is set up.
  • Each free electron experiences a force F = eE opposite to the field direction (since electron charge is negative).
  • This force superimposes a small, steady drift on the otherwise random thermal motion.
  • The result: electrons acquire a net average velocity called drift velocity, directed opposite to E.
CISCE: Class 12

Derivation

Step 1: Between two collisions, an electron accelerates due to the field.

\[\vec a\] = \[\frac {−e\vec E}{m}\]

Step 2: Average time between collisions = relaxation time τ.

Step 3: Average drift velocity gained: \[\vec v_d\] = \[\vec a\]τ

Step 4: Substituting acceleration: vd = \[\frac {eEτ}{m}\]

Where:

  • e = charge on electron
  • E = applied electric field
  • τ = relaxation time
  • m = mass of electron
CISCE: Class 12

Example

Given: Electric field E = 2.5 V/m; relaxation time τ = 2.5 × 10−14 s
To Find: Drift velocity vd
Formula: vd = \[\frac {eEτ}{m}\]
Solution: vd = \[\frac {(1.6×10^{−19})(2.5)(2.5×10^{−14})}{9.1×10^{−31}}\]
Answer: vd ≈ 0.011 m/s (i.e., 1.1 cm/s)

CISCE: Class 12

Real Life Analogy

  • Parking Garage Analogy: Imagine hundreds of cars randomly circling inside a large parking garage (thermal motion). Now tilt the entire garage slightly—cars still move randomly, but a slow, steady drift pulls them toward the lower end (drift velocity under a field). The individual cars still move fast and randomly, but the net flow is slow and directional.
  • Fermi Sea Concept (Hot Info): At absolute zero, free electrons in a metal do not sit still — quantum mechanics (Pauli's Exclusion Principle) forces them to occupy a range of energy states up to the Fermi energy, so even "resting" electrons possess high thermal speeds.
Advertisements
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×