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ISC (Science) ISC Class 12 - CISCE Important Questions for Physics (Theory)

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Physics (Theory)
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Draw a labelled circuit diagram of a potentiometer to compare emfs of two cells. Write the working formula (Derivation not required).

Appears in 1 question paper
Chapter: [6] DC Circuits and Measurements
Concept: Potentiometer

In the circuit shown in the figure below, E1 and E2 are two cells having emfs 2 V and 3 V respectively, and negligible internal resistance. Applying Kirchhoff’s laws of electrical networks, find the values of currents l1 and I2.

Appears in 1 question paper
Chapter: [6] DC Circuits and Measurements
Concept: Kirchhoff’s Laws

Write balancing condition of a Wheatstone bridge.

Appears in 1 question paper
Chapter: [6] DC Circuits and Measurements
Concept: Wheatstone Bridge

In the circuit shown in Figure below, E1 and E2 are batteries having emfs of 25V and 26V. They have an internal resistance of 1 Ω and 5 Ω respectively. Applying Kirchhoff’s laws of electrical networks, calculate the currents I1 and I2.

Appears in 1 question paper
Chapter: [6] DC Circuits and Measurements
Concept: Kirchhoff’s Laws

A meter bridge is balanced with a known resistance (R) in the left hand gap and an unknown resistance (S) in the right hand gap. Balance point is found to be at a distance of 1 cm from the left hand side. When the battery and the galvanometer are interchanged, balance point will ______.

Appears in 1 question paper
Chapter: [6] DC Circuits and Measurements
Concept: Metre Bridge: Slide-Wire Bridge

Three identical cells each of emf 'e' are connected in parallel to form a battery. What is the emf of the battery?

Appears in 1 question paper
Chapter: [6] DC Circuits and Measurements
Concept: Potentiometer

The figure below shows two batteries, E1 and E2, having emfs of 18V and 10V and internal resistances of 1 Ω and 2 Ω, respectively. W1, W2 and W3 are uniform metallic wires AC, FD and BE having resistances of 8 Ω, 6 Ω and 10 Ω respectively. B and E are midpoints of the wires W1 and W2. Using Kirchhoff's laws of electrical circuits, calculate the current flowing in the wire W3:

Appears in 1 question paper
Chapter: [6] DC Circuits and Measurements
Concept: Kirchhoff’s Laws

The Figure below shows a potentiometer circuit in which the driver cell D has an emf of 6 V and internal resistance of 2 Ω. The potentiometer wire AB is 10 m long and has a resistance of 28 Ω. The series resistance RS is of 2 Ω.

  1. The current Ip flowing in the potentiometer wire AB when the jockey (J) does not touch the wire AB.
  2. emf of the cell X if the balancing length AC is 4.5 m.
Appears in 1 question paper
Chapter: [6] DC Circuits and Measurements
Concept: Potentiometer

In a potentiometer, a cell is balanced against 110 cm when the circuit is open. A cell is balanced at 100 cm when short-circuited through a resistance of 10 Ω. Find the internal resistance of the cell.

Appears in 1 question paper
Chapter: [6] DC Circuits and Measurements
Concept: Potentiometer

Using Ampere's circuital law, obtain an expression for the magnetic flux density 'B' at a point 'X' at a perpendicular distance 'r' from a long current-carrying conductor.
(Statement of the law is not required).

Appears in 1 question paper
Chapter: [7] Moving Charges and Magnetic Field
Concept: Ampere’s Circuital Law

Two infinitely long current carrying conductors X and Y are kept parallel to each other, 24 cm apart in a vacuum. They carry currents of 5A and 7A respectively, in the same direction, as shown in the figure below. Find the position of a neutral point, i.e., a point where resultant magnetic flux density is zero. (Ignore earth’s magnetic field). 

Appears in 1 question paper
Chapter: [7] Moving Charges and Magnetic Field
Concept: Force on a Current - Carrying Conductor in a Uniform Magnetic Field

Using Ampere’s circuital law, obtain an expression for magnetic flux density ‘B’ at a point near an infinitely long and straight conductor, carrying a current I.

Appears in 1 question paper
Chapter: [7] Moving Charges and Magnetic Field
Concept: Ampere’s Circuital Law

When current flowing through a solenoid decreases from 5A to 0 in 20 milliseconds, an emf of 500V is induced in it.

  1. What is this phenomenon called?
  2. Calculate coefficient of self-inductance of the solenoid.
Appears in 1 question paper
Chapter: [7] Moving Charges and Magnetic Field
Concept: Ampere’s Circuital Law

How will you convert a moving coil galvanometer into a voltmeter?

Appears in 1 question paper
Chapter: [8] Torque on a Current-Loop : Moving-Coil Galvanometer
Concept: Moving Coil Galvanometer

Why are the pole pieces of a horseshoe magnet in a moving coil galvanometer made cylinder in shape? 

Appears in 1 question paper
Chapter: [8] Torque on a Current-Loop : Moving-Coil Galvanometer
Concept: Moving Coil Galvanometer

A moving coil galvanometer has a coil of resistance 59 Ω. It shows a full-scale deflection for a current of 50 mA. How will you convert it to an ammeter having a range of 0 to 3A?

Appears in 1 question paper
Chapter: [8] Torque on a Current-Loop : Moving-Coil Galvanometer
Concept: Moving Coil Galvanometer

A moving coil galvanometer of resistance 55 Ω produces a full scale deflection for a current of 250 mA. How will you convert it into an ammeter with a range of 0 - 3A?

Appears in 1 question paper
Chapter: [8] Torque on a Current-Loop : Moving-Coil Galvanometer
Concept: Moving Coil Galvanometer

Assertion: When an electric current is passed through a moving coil galvanometer, its coil gets deflected.

Reason: A circular coil produces a uniform magnetic field around itself when an electric current is passed through it.

Appears in 1 question paper
Chapter: [8] Torque on a Current-Loop : Moving-Coil Galvanometer
Concept: Moving Coil Galvanometer

The figure below shows a circuit containing an ammeter A, a galvanometer G and a plug key K. When the key is closed:

Appears in 1 question paper
Chapter: [8] Torque on a Current-Loop : Moving-Coil Galvanometer
Concept: Moving Coil Galvanometer

A galvanometer of resistance 100 Ω gives a full-scale deflection for a potential difference of 200 mV.

  1. What must be the resistance connected to convert the galvanometer into an ammeter of the range 0-200 mA?
  2. Determine resistance of the ammeter.
Appears in 1 question paper
Chapter: [8] Torque on a Current-Loop : Moving-Coil Galvanometer
Concept: Moving Coil Galvanometer
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