Advertisements
Advertisements
Question
Write balancing condition of a Wheatstone bridge.
Advertisements
Solution
When no current flows through the galvanometer, the wheatstone bridge is considered to be in a balanced state. This condition can be met by modifying the known and variable resistance.

The balancing condition,
`"R"_1/"R"_2 = "R"_3/"R"_4`
APPEARS IN
RELATED QUESTIONS
Choose the correct:
Four resistances 10 Ω, 10 Ω, 10 Ω and 15 Ω form a Wheatstone’s network. What shunt is required across 15 Ω resistor to balance the bridge
Explain with a neat circuit diagram. How you will determine the unknown resistances using a meter bridge.
ln the metre bridge experiment, one metre long wire acts as ____________.
The resistances in left and right gap of a metrebridge are 20 `Omega` and 30 `Omega` respectively. When the resistance in the left gap is reduced to half its value, the balance point shifts by ______.
The potential difference between the points A and B in the electric circuit shown is ______.

Two resistances prepared from the wire of the same material having diameters in the ratio 2 : 1 and lengths in the ratio 2 : 1 are connected in the left gap and right gap of Wheatstone's meter bridge respectively. The distance of the null point from the left end of the wire is ______
In a balanced metre bridge, 5 Ω is connected in the left gap and R Ω in the right gap. When R Ω is shunted with equal resistance, the new balance point is at 1.6 I1 where 'I1' is the earlier balancing length. The value of 'I1' is ______
The Wheatstone bridge is in a more balanced state when the ratio of arms P and Q is ______
Draw a neat labelled diagram of Kelvin's meter bridge circuit for the measurement of galvanometer resistance.
