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प्रश्न
Write balancing condition of a Wheatstone bridge.
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उत्तर
When no current flows through the galvanometer, the wheatstone bridge is considered to be in a balanced state. This condition can be met by modifying the known and variable resistance.
The balancing condition,
`"R"_1/"R"_2 = "R"_3/"R"_4`
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संबंधित प्रश्न
What should be the value of R in the figure for which the current in it is zero?
Four resistances 4 Ω, 8Ω, XΩ and 12Ω are connected in a series to form Wheatstone’s network. If the network is balanced, the value of X is ______.
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The current through 1 `Omega` resistance in the following circuit is ______.
A resistance of 20 Ω is connected in the left gap of a meter bridge and an unknown resistance greater than 20 Ω is connected in the right gap. When these resistances are interchanged, the balance point shifts by 20 cm. The unknown resistance is ______.
- Assertion (A): The given figure does not show a balanced Wheatstone bridge.
- Reason (R): For a balanced bridge small current should flow through the galvanometer.
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In the given Wheatstone's network, what should be the value of R for the network to be balanced?
