Question

A battery of 6 V is connected to the circuit as shown below. The current I drawn from the battery is:

Options

• 1A

• 2A

• `6/11 A`

• `4/3 A`

Answer 1

1A

Explanation:

Balanced wheat stone bridge in circuit, so there is no current in the 5Q resistor, so it can be removed from the circuit.

The equivalent resistance will be

`R_(eq) = (6xx12)/(6+12) + 2`

= 6 Ω

Now, apply K.V.L. 

we have

`I = V/R_(eq)`

`= 6/6`

= 1A