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प्रश्न
A battery of 6 V is connected to the circuit as shown below. The current I drawn from the battery is:

विकल्प
1A
2A
`6/11 A`
`4/3 A`
MCQ
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उत्तर
1A
Explanation:
Balanced wheat stone bridge in circuit, so there is no current in the 5Q resistor, so it can be removed from the circuit.

The equivalent resistance will be
`R_(eq) = (6xx12)/(6+12) + 2`
= 6 Ω
Now, apply K.V.L.
we have
`I = V/R_(eq)`
`= 6/6`
= 1A
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