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The Value Of \[2 \Sin^2 B + 4 \Cos \Left( a + B \Right) \Sin a \Sin B + \Cos 2 \Left( a + B \Right)\] is - Mathematics

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Question

The value of  \[2 \sin^2 B + 4 \cos \left( A + B \right) \sin A \sin B + \cos 2 \left( A + B \right)\] is 

Options

  • 0

  •  cos 3A

  • cos 2A

  •  none of these

MCQ
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Solution

cos 2A

\[\text{ We have, }  \]

\[2 \sin^2 B + 4\cos\left( A + B \right) \text{ sin } A \text{ sin } B + \cos2\left( A + B \right)\]

\[ = 1 - \cos2B + \cos2\left( A + B \right) + 4\cos\left( A + B \right) \text{ sin } A \text{ sin } B\]

\[ = 1 + \left( \cos2\left( A + B \right) - \cos2B \right) + 4\cos\left( A + B \right) \text{ sin } A \text{ sin } B\]

\[ = 1 - 2\text{ sin } A\sin\left( A + 2B \right) + 4\cos\left( A + B \right) \text{ sin } A \text{ sin } B\]

\[ \left[ \because \text{ cos } C - \text{ cos } D = - 2\sin\frac{C + D}{2}\sin\frac{C - D}{2} \right]\]

\[ = 1 - 2\text{ sin } A\left[ \sin\left( A + 2B \right) - 2\text{ sin } B\cos\left( A + B \right) \right]\]

\[ = 1 - 2\text{ sin } A\left[ \sin\left( A + 2B \right) - \left\{ \sin\left( B + A + B \right) + \sin\left( B - \left( A + B \right) \right) \right\} \right] \]

\[ \left[ \because 2\text{ sin } C\text{ cos } D = \sin\left( C + D \right) + \sin\left( C - D \right) \right]\]

\[ = 1 - 2\text{ sin } A\left[ \sin\left( A + 2B \right) - \left\{ \sin\left( A + 2B \right) + \sin\left( - A \right) \right\} \right]\]

\[ = 1 - 2\text{ sin } A\left[ \text{ sin } A \right]\]

\[ = 1 - 2 \sin^2 A\]

\[ = \cos2A\]

 

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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Chapter 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.5 [Page 44]

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RD Sharma Mathematics [English] Class 11
Chapter 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.5 | Q 22 | Page 44

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