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2 ( 1 − 2 sin 2 7 x ) sin 3 x is equal to - Mathematics

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Question

\[2 \left( 1 - 2 \sin^2 7x \right) \sin 3x\]  is equal to

Options

  • \[\sin 17x - \sin 11x\]

  • \[\sin 11x - \sin 17x\]

  • \[\cos 17x - \cos 11x\]

  • \[\cos 17x + \cos 11x\]

MCQ
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Solution

\[\sin 17x - \sin 11x\] 

\[\text{ We have } , \]

\[ 2\left( 1 - 2 \sin^2 7x \right) \sin 3x = 2\left( \cos 14x \right) \sin3x \]

\[ \left[ \because \cos2x = 1 - 2 \sin^2 x \right]\]

\[ = 2 \sin3x \cos 14x\]

\[ = \sin 17x - \sin 11x\]

\[ \left[ \because 2 sinA cosB = \sin\left( A + B \right) - \sin\left( A - B \right) \right] \]

\[ \therefore 2\left( 1 - 2 \sin^2 7x \right) \sin 3x = \sin 17x - \sin 11x\]

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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Chapter 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.5 [Page 44]

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RD Sharma Mathematics [English] Class 11
Chapter 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.5 | Q 24 | Page 44

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