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Prove That: Sin 4 X = 4 Sin X Cos 3 X − 4 Cos X Sin 3 X

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Question

Prove that: \[\sin 4x = 4 \sin x \cos^3 x - 4 \cos x \sin^3 x\]

 
Numerical
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Solution

\[LHS = sin 4x\]

\[ = 2\sin2x \cos2x \left( \because \sin2\theta = 2sin\theta cos\theta \right)\]

Now, using the identities

\[\sin2\alpha = 2\sin\alpha\cos\alpha \text{ and }  \cos2\alpha = \cos^2 \alpha - \sin^2 \alpha\], we get

\[LHS = 2(2\text{ sin } x \text{ cos } x) . ( \cos^2 x - \sin^2 x)\]

\[ = 4\text{ sin } x \cos^3 x - 4 \sin^3 x \text{ cos } x = RHS\]

\[\text{ Hence proved } .\]

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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Chapter 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.1 [Page 28]

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R.D. Sharma Mathematics [English] Class 11
Chapter 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.1 | Q 18 | Page 28

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