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The value of cos248° – sin212° is ______. [Hint: Use cos2A – sin2 B = cos(A + B) cos(A – B)]

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Question

The value of cos248° – sin212° is ______.

[Hint: Use cos2A – sin2 B = cos(A + B) cos(A – B)]

Options

  • `(sqrt(5) + 1)/8`

  • `(sqrt(5) - 1)/8`

  • `(sqrt(5) + 1)/5`

  • `(sqrt(5) + 1)/(2sqrt(2)`

MCQ
Fill in the Blanks
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Solution

The value of cos248° – sin212° is `bbunderline((sqrt(5) + 1)/8)`.

Explanation:

The given expression is cos248° – sin212°.

cos248° – sin212° = cos(48° + 12°).cos(48° – 12°)   ......[∵ cos2A – sin2B = cos(A + B).cos(A – B)]

= cos 60°.cos 36°

= `1/2 xx (sqrt(5) + 1)/4`

= `(sqrt(5) + 1)/8`

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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Chapter 3: Trigonometric Functions - Exercise [Page 58]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 3 Trigonometric Functions
Exercise | Q 56 | Page 58

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