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The Value of Sin 5 α − Sin 3 α Cos 5 α + 2 Cos 4 α + Cos 3 α =

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Question

The value of \[\frac{\sin 5 \alpha - \sin 3\alpha}{\cos 5 \alpha + 2 \cos 4\alpha + \cos 3\alpha} =\]

 

Options

  • \[\cot \alpha/2\]

     

  • \[\cot \alpha\]

     

  • \[\tan \alpha/2\]

     

  • None of these 

MCQ
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Solution

\[\frac{\sin5\alpha - \sin3\alpha}{\cos5\alpha + 2\cos4\alpha + \cos3\alpha} = \frac{\sin5\alpha - \sin3\alpha}{\cos5\alpha + \cos3\alpha + 2\cos4\alpha}\]
\[ = \frac{2\sin\alpha\cos4\alpha}{2\cos4\alpha\cos\alpha + 2\cos4\alpha}\]
\[ = \frac{2\sin\alpha\cos4\alpha}{2\cos4\alpha\left( \cos\alpha + 1 \right)}\]
\[ = \frac{\sin\alpha}{\cos\alpha + 1}\]
\[ = \frac{2\sin\frac{\alpha}{2}\cos\frac{\alpha}{2}}{\cos^2 \frac{\alpha}{2} - \sin^2 \frac{\alpha}{2} + \sin^2 \frac{\alpha}{2} + \cos^2 \frac{\alpha}{2}}\]
\[ = \frac{2\sin\frac{\alpha}{2}\cos\frac{\alpha}{2}}{2 \cos^2 \frac{\alpha}{2}}\]
\[ = \frac{\sin\frac{\alpha}{2}}{\cos\frac{\alpha}{2}}\]
\[ = \tan\frac{\alpha}{2}\]

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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Chapter 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.5 [Page 45]

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R.D. Sharma Mathematics [English] Class 11
Chapter 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.5 | Q 33 | Page 45

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