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The value of cos12° + cos84° + cos156° + cos132° is ______.

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Question

The value of cos12° + cos84° + cos156° + cos132° is ______.

Options

  • `1/2`

  • 1

  • `-1/2`

  • `1/8`

MCQ
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Solution

The value of cos12° + cos84° + cos156° + cos132° is `-1/2`.

Explanation:

The given expression is cos12° + cos84° + cos156° + cos132° 

(cos132° + cos12°) + (cos156° + cos84°)

= `(2cos  (132^circ + 12^circ)/2 . cos  (132^circ - 12^circ)/2) + (2cos  (156^circ + 84^circ)/2 . cos  (156^circ - 84^circ)/2)`

= 2cos72° . cos60° + 2cos120° . cos36°

= `2 cos 72^circ xx 1/2 + 2 xx (-1/2) cos 36^circ`

= cos72° – cos36°

= cos(90° – 18°) – cos36°

= sin18° – cos36°

= `(sqrt(5) - 1)/4 - (sqrt(5) + 1)/4`   ......`[because sin18^circ = (sqrt(5) - 1)/4, cos 36^circ = (sqrt(5) + 1)/4]`

= `(sqrt(5) - 1 - sqrt(5) - 1)/4`

= `-1/2`

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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Chapter 3: Trigonometric Functions - Exercise [Page 57]

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NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 3 Trigonometric Functions
Exercise | Q 46 | Page 57

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