Tan2θ – sin2θ = tan2θ × sin2θ हे सिद्ध करण्यासाठी खालील कृती पूर्ण करा. कृती: डावी बाजू = □ = □(1-sin2θtan2θ) = tan2θ(1-□sin2θcos2θ) = tan2θ(1-cos2θ□) = tan2θ(1-□) = tan2θ×□ .....[1 – cos2θ = sin2]

tan²θ – sin²θ = tan²θ × sin²θ हे सिद्ध करण्यासाठी खालील कृती पूर्ण करा.

कृती: डावी बाजू = `square`

= `square (1 - (sin^2theta)/(tan^2theta))`

= `tan^2theta (1 - square/((sin^2theta)/(cos^2theta)))`

= `tan^2theta (1 - (sin^2theta)/1 xx (cos^2theta)/square)`

= `tan^2theta (1 - square)`

= `tan^2theta xx square` .....[1 – cos²θ = sin²θ]

= उजवी बाजू

Sum

डावी बाजू = tan²θ – sin²θ

= `underline(tan^2theta) (1 - (sin^2theta)/(tan^2theta))`

= `tan^2theta (1 -(underline(sin^2theta))/((sin^2theta)/(cos^2theta)))`

= `tan^2theta (1 - (sin^2theta)/1 xx (cos^2theta)/underline(sin^2theta))`

= `tan^2theta (1 - underline(cos^2theta))`

= tan²θ × sin²θ .....[1 – cos²θ = sin²θ]

= उजवी बाजू

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