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Let F : N → N Be Defined by `F(N) = { (N+ 1, If N Is Odd),( N-1 , If N Is Even):}` Show That F Is a Bijection.

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Question

Let f : N → N be defined by

`f(n) = { (n+ 1, if n  is  odd),( n-1 , if n  is  even):}`

Show that f is a bijection. 

                      [CBSE 2012, NCERT]

Sum
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Solution

We have,

`f (n) = {(n + 1 , if  n  is  odd),(n - 1, if n  is  even):}`

Injection test : 

Case I: If n is odd,

Let x, y ∈ N such that f (x)=f (y)

As, f (x)=f (y)

⇒ x + 1= y + 1

⇒ x = y

Case II: If n is even,

Let x, y ∈ N such that f (x)=f (y)

As, f (x)=f (y)

⇒ x − 1 = y − 1

⇒ x = y

So, f is injective.

Surjection test:

Case I: If n is odd,

As, for every n ∈ N, there exists y = n − 1 in N such that

f (y) = f (n−1)=n −1+1= n

Case II: If n is even,

As, for every n ∈ N, there exists y = n + 1 in N such that f (y)=f (n+1)=n +1−1 = n

So, f is surjective.

So, f is a bijection.

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Chapter 2: Functions - Exercise 2.1 [Page 32]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 2 Functions
Exercise 2.1 | Q 23 | Page 32

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