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Show that the function f : R → R given by f(x) = x^3 is injective.

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Question

Show that the function f : R → R given by f(x) = x3 is injective.

Sum
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Solution 1

f : R → R is given as f(x) = x3.

Suppose f(x) = f(y), where x, y ∈ R.

⇒ x3 = y3  ... (1)

Now, we need to show that x = y.

Suppose x ≠ y; their cubes will also not be equal.

⇒ x3 ≠ y3

However, this will be a contradiction to (1).

∴ x = y

Hence, f is injective.

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Solution 2

Let x1, x2 ∈ R be such that

f(x1) = f(x2)

⇒ `x_1^3 = x_2^3`

⇒ x1 = x2

∴ f is one-one.

Hence, f(x) = x3 is injective.

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Chapter 1: Relations and Functions - Miscellaneous Exercise on Chapter 1 [Page 15]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 1 Relations and Functions
Miscellaneous Exercise on Chapter 1 | Q 2. | Page 15

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